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Mathematics 21 Online
OpenStudy (anonymous):

I need help with these hw questions! photo attached

OpenStudy (anonymous):

OpenStudy (reemii):

if you give an random answer and wait for the correction you'll not learn much. it's just an advice.

OpenStudy (anonymous):

@dpaInc

OpenStudy (whpalmer4):

okay, how about the inverse functions question up at the top. What do you know about doing such problems?

OpenStudy (anonymous):

Not much, I did it earlier and got the answer A

OpenStudy (whpalmer4):

Can you show me your work? That's not correct.

OpenStudy (anonymous):

I just checked my work.....now Im getting B

OpenStudy (whpalmer4):

Ah, that's better.

OpenStudy (anonymous):

I cant type it all out, its complicated srry it would take forever

OpenStudy (whpalmer4):

No, it's not that hard. y = 2x-4, solve for x: \[y+4=2x\]\[\frac{y+4}{2}=x\]Swap variables: \[y=\frac{x+4}{2}\]

OpenStudy (anonymous):

My computer doesnt let me use the equation button :(

OpenStudy (whpalmer4):

y+4=2x (y+4)/2=x Swap variables: y = (x+4)/2 :-)

OpenStudy (anonymous):

For 14. I got C

OpenStudy (whpalmer4):

I don't do asymptotes. what's your next question?

OpenStudy (anonymous):

15-17

OpenStudy (anonymous):

15. I got D. 64

OpenStudy (whpalmer4):

sorry, openstudy is being flaky for me this afternoon. we can do the asymptote one. how are you going to identify the asymptotes from the equation?

OpenStudy (anonymous):

I have no clue :(

OpenStudy (whpalmer4):

Okay, what does it mean to have a vertical asymptote?

OpenStudy (anonymous):

I worked it out with my tutor he got B

OpenStudy (whpalmer4):

Let me ask a related question: does the function have a specific value at a vertical asymptote?

OpenStudy (whpalmer4):

Here's another question: what is the value of that function at x=1 or x=-3?

OpenStudy (whpalmer4):

Your tutor apparently needs some tutoring himself.

OpenStudy (anonymous):

I really need the answers Im sorry normally I would work out the problems with you.

OpenStudy (whpalmer4):

What, you think I have the answer sheet or something? If I'm going to work them out, you can work them out with me. The vertical asymptotes happen wherever the denominator = 0 — they represent dividing by 0. Find the values of x where the denominator = 0 (remember: it is a product, so any of the components of the product can be 0 to make the product 0) and you've found the vertical asymptotes. They will be of the form x = <some constant value>.

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Ill try that out. Ill give you my answer in a sec

OpenStudy (whpalmer4):

The horizontal asymptotes are a bit trickier to think about, perhaps. They represent the horizontal line above or below which the function won't go. In this case, we have a division, so if the denominator gets really really big, the result of that division gets closer and closer to 0 (but never quite gets there). The horizontal asymptote will be of the form y = <some constant value>.

OpenStudy (anonymous):

I got y=-3

OpenStudy (anonymous):

wait no y=1

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