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Physics 18 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

@thomaster, @some_someone , @Jhannybean

OpenStudy (anonymous):

@thomaster can you help me please

OpenStudy (anonymous):

@amistre64 @SnuggieLad anyone

OpenStudy (anonymous):

@ash2326 please

OpenStudy (ash2326):

@IxairaS I don't have idea about the first one and second one. I can help you with the last

OpenStudy (ash2326):

Amount of iodine doesn;t matter here In 8.10 days half of the iodine will decay. So half will remain In next 8.10 days half of the remaining will decay. @IxairaS can you tell how much of Iodine will remain now?

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

C 40.5

OpenStudy (anonymous):

can you help me with a couple more

OpenStudy (ash2326):

That one is not over

OpenStudy (anonymous):

i know so is it C am I incorrect

OpenStudy (ash2326):

First tell me how much will remain after the next 8.10 days?

OpenStudy (anonymous):

i dont know :(

OpenStudy (ash2326):

1-> 1/2 in 8.10 days so it will get half further in next 8.10 days, so 1/4 th will remain Do you get this?

OpenStudy (anonymous):

no but I think its B

OpenStudy (ash2326):

We will arrive at the answer, do you get this part?

OpenStudy (anonymous):

a bit

OpenStudy (ash2326):

Ok, so it'll further get half in 8.10 days. How much will remain now?

OpenStudy (anonymous):

4.05

OpenStudy (ash2326):

\[\frac1 2\times \frac 1 4\]

OpenStudy (anonymous):

2/4 or 1/2

OpenStudy (ash2326):

What's half of 1/4?

OpenStudy (anonymous):

0.25

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