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OpenStudy (anonymous):
@thomaster, @some_someone , @Jhannybean
OpenStudy (anonymous):
@thomaster can you help me please
OpenStudy (anonymous):
@amistre64 @SnuggieLad anyone
OpenStudy (anonymous):
@ash2326 please
OpenStudy (ash2326):
@IxairaS I don't have idea about the first one and second one.
I can help you with the last
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OpenStudy (ash2326):
Amount of iodine doesn;t matter here
In 8.10 days half of the iodine will decay. So half will remain
In next 8.10 days half of the remaining will decay.
@IxairaS can you tell how much of Iodine will remain now?
OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
C 40.5
OpenStudy (anonymous):
can you help me with a couple more
OpenStudy (ash2326):
That one is not over
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OpenStudy (anonymous):
i know so is it C am I incorrect
OpenStudy (ash2326):
First tell me how much will remain after the next 8.10 days?
OpenStudy (anonymous):
i dont know :(
OpenStudy (ash2326):
1-> 1/2 in 8.10 days
so it will get half further in next 8.10 days, so 1/4 th will remain
Do you get this?
OpenStudy (anonymous):
no but I think its B
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OpenStudy (ash2326):
We will arrive at the answer, do you get this part?
OpenStudy (anonymous):
a bit
OpenStudy (ash2326):
Ok, so it'll further get half in 8.10 days. How much will remain now?
OpenStudy (anonymous):
4.05
OpenStudy (ash2326):
\[\frac1 2\times \frac 1 4\]
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