Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Who wants an easy medal!

OpenStudy (anonymous):

cos^2(theta) -1

OpenStudy (anonymous):

@Zarkon

OpenStudy (loser66):

the question is unclear. and I give you medal for free. heheh, I don't know how to solve

OpenStudy (anonymous):

oh thanks!

OpenStudy (anonymous):

oh thanks!

OpenStudy (luigi0210):

Trig identities,\[\cos^2\theta-1=\sin^2\theta\]

OpenStudy (loser66):

nope

OpenStudy (anonymous):

it wants me to simpify

OpenStudy (luigi0210):

Why not? and that is simplified

OpenStudy (goldphenoix):

\[-\cos^2(aht^2e)\]

OpenStudy (luigi0210):

Oh I see my mistake.. again

OpenStudy (luigi0210):

yea \[-\cos^2\theta \] sorry about that :/

OpenStudy (loser66):

redo

OpenStudy (loser66):

@Luigi0210

OpenStudy (loser66):

@lala2 he gave you the formula, you replace and figure out the answer. 1= sin^2 +cos^2

OpenStudy (anonymous):

what about this one sec(theta)sin(theta)cot(theta)

OpenStudy (luigi0210):

\[\sec \theta*\sin \theta*\cot \theta=\frac{ 1 }{ \cos \theta }*\sin \theta*\frac{ \cos \theta }{ \sin \theta }=\frac{ \sin \theta }{ \cos \theta }*\frac{ \cos \theta }{ \sin }\]

OpenStudy (luigi0210):

*sin(theta)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!