Check my work. It's the first one underlined red. I'm using the slope formula. Did I use it right?
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Question

Check my work. It's the first one underlined red. I'm using the slope formula. Did I use it right? 
http://prntscr.com/176dvo

anonymous · Answer

@mathslover @A.Avinash_Goutham @Hero

mathslover · Answer

Is that a test question Sephl?

compassionate · Answer

Yea, I just want to know if I got it or not. I mean, would that be correct to find the slope?

compassionate · Answer

If I was using y2 - y1, and my y1 was negative, lets say I have 3 and -5, I'd have 3 - (-5), which becomes 3 + 5, right?

anonymous · Answer

If I have a negative that does make it a positive?

mathslover · Answer

can you tell me what will be c? (y--intercept) ?

mathslover · Answer

See I have : y = mx + c

m =slope, c = y intercept

Now, as you found slope (m) = $\cfrac{3}{2}$ . I will put that in the equation y = mx + c

$y = \cfrac{3}{2} x + c$ 

Let us put , x = 8 and y = 4 (these coordinates are given to us) 

$8 = \cfrac{3}{2} (4) + c$ 

Find "c" from here . 

Can you?