help i have 4 questions
What is the approximate distance between the points (4, 5, 4) and (3, 7, 6)? 8 9 17<<<<<<<i think this is the answer. 29
subtract, square, add, and sqrt is the process
(4, 5, 4) -(3, 7, 6) ---------- 1 2 2 1+4+4 = 9 sqrt(9) = 3 hmm, thats not an option tho
9 is
make sure youre information is correctly posted
yesp these are the choices 8 9 17 29
http://www.wolframalpha.com/input/?i=distance+between+%284%2C+5%2C+4%29+and+%283%2C+7%2C+6%29 distance, as is, is 3
wait oops its -4,5, 4 and 3,-7,-6
oops im so sorry :(
:) same process, different values
-4,5, 4 -3,7,6 ---------- 7 12 10 49+144+100= 293 sqrt(293) is greater then 10, 11, 12, 13, 15, 17 is looking plausible yes
so i was right 17?
29^2 = 4xx 15^2 = 225 sqrt(293) = 17.11.... so yes
cool okay here is the next one
When the point (-1, 3) is dilated with the center of dilation at the origin, the image of the point is (-4, 12). What is the scale factor of this dilation? 4 0.25 - 4 -0.25
-1 * s = -4 3 * s = 12 solve for s
i get that part but i get confused when solving for s my original answer was 0.25 but i think im wrong b/c im unsure how to do it :(
3, times what, equals 12? you have to know your basic times tables at least :)
4 lol
then the scale factor has to be 4 :)
lol wow i was way way off lol thank you for your help on that one :P
lol, thats ok, my first guess would have been 132
lol ^.^ well the next two have pic that go with them .
we gots a draw button underneath, or if you can do a screenshot and attach as a jpg thats fine
Find the measure of APB if the measure of arc AB = 130°. 100° 70° 65° 50°
theres a thrm that goes; the angle on the outside of what we are looking at is the difference between the outer arc and the inner arc
lol thats a long term to remember haha :P
they give the inner are as 130 the outter arc is 360 - 130 (360 - 130) - 130 should do it
100 ^.^
100 seems to work for me
we can dbl chk another way tho
the central angle is equal to the inner arc: 130 the tangents are always 90; so another 180 |dw:1369842126282:dw|
i guess i forgot the divide by 2 part of the thrm :/
(outer-inner) ----------- 2
Which pair of triangles is similar?
okay sorry about that
similar triangle have a common ratio of parts
i thought it was number 1
spose your lengths are: a,b,c and A,B,C a b c -- = -- = -- A B C
ok
number 1 is good
but so is number 4 lol
3 4 5 : 1 9 12 15 : 3
number 4 is not
3 4 5 -- = --- not= ---- 9 12 16
really? i guess thats why i was confused i was stuck between the two
helps if i use the right ratios .... #4 is squares
3^2 = 9 4^2 = 16 5^2 = 25 these are not common rations\[\frac{5}{25}=\frac15\] \[\frac{4}{16}=\frac14\] \[\frac{3}{9}=\frac13\]
oh i see and we found out that number 1 was 1/3 so the answer is number 1 ???
correct
thank you so much ^.^
youre welcome, and good luck :)
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