Question

In the diagram below, line segment AT is a diameter of the circle with center O. What is the area of the shaded part of the circle?

Answer 1

Do you know how to find the area of that triangle first?

Answer 2

Finding the area of the shaded region will be the area of the circle - area of the triangle.

Answer 3

Nope, I found the area on half the circle and I'm supposed the find the other using arcs and stuff and it's so confusing.

Answer 4

Do you have to solve it that method? Beccause Area of a circle = pi*r^2 or pi* D and area of a triangle = (1/2)*b*h, so
Area of a circle : \(A= \pi r^2 = \pi (16) = 16\pi\)
Area of a triangle : 30-60-90 triangle : base= 8, height = \(8\sqrt{3}\) : \(A=\frac{1}{2}(8)(8\sqrt{3})\)

Area of circle - Area of triangle = \(16\pi- [\frac{1}{2}(8)(8\sqrt{3})]\)\[16\pi - [4(8\sqrt{3}] = 16\pi-32\sqrt{3}\]

Answer 5

:( the drawing area needs to be biggerr!!

Answer 6

matthew i dont think they want you to solve it that way

Answer 7

Woah... I understood almost none of that..

Answer 8

okay matthew if u wanna stick to that finding area between arc and bisector way then u gotta do it like this

Answer 9

Ok,let's take it step by step, we can come back and relate it to that post i made afterwards.