OpenStudy (anonymous):

A box contains 15 cards. There are 5 red cards labeled 1, 2, 3, 4, and 5. There are 5 blue cards labeled 1, 2, 3, 4, and 5. There are 5 green cards labeled 1, 2, 3, 4, and 5. One card is drawn from the box. What is the probability that it is a green card with an even number or a blue card?

4 years ago
OpenStudy (foreverandalways13):

this one?

4 years ago
OpenStudy (anonymous):

yea

4 years ago
OpenStudy (foreverandalways13):

k

4 years ago
OpenStudy (anonymous):

its hard

4 years ago
OpenStudy (foreverandalways13):

im not sure

4 years ago
OpenStudy (foreverandalways13):

meant to post a while ago lol

4 years ago
OpenStudy (anonymous):

haha

4 years ago
OpenStudy (kropot72):

There are 2 green cards with even numbers and there are 5 blue cards. Therefore there are 2 + 5 = 7 cards involved in the calculation. The probability of selecting a green card with an even number or a blue card is 7/15

4 years ago
OpenStudy (anonymous):

he must be typing a lot of words

4 years ago
OpenStudy (anonymous):

thanks @kropot72

4 years ago
OpenStudy (anonymous):

thanks @foreverandalways13

4 years ago
OpenStudy (anonymous):

4 years ago
OpenStudy (anonymous):

A box contains 10 cards numbered 1 through 10. Which events are mutually exclusive?

4 years ago
OpenStudy (anonymous):

A. A card is drawn from the box and the number is even. A card is drawn from the box and the number is 4. B. A card is drawn from the box and the number is even. A card is drawn from the box and the number is 2. C. A card is drawn from the box and the number is odd. A card is drawn from the box and the number is 1. D. A card is drawn from the box and the number is even. A card is drawn from the box and the number is 1.

4 years ago
OpenStudy (foreverandalways13):

wow they make things complicated huh?

4 years ago
OpenStudy (anonymous):

very

4 years ago
OpenStudy (foreverandalways13):

lol

4 years ago
OpenStudy (kropot72):

In events A, B and C it is possible that the card that is drawn first is the card that is said to be drawn next. In these cases the overall event is impossible the reason being that the sub-events cannot happen together and are therefore mutually exclusive.

4 years ago