Question

A box contains 15 cards. There are 5 red cards labeled 1, 2, 3, 4, and 5. There are 5 blue cards labeled 1, 2, 3, 4, and 5. There are 5 green cards labeled 1, 2, 3, 4, and 5. One card is drawn from the box.



What is the probability that it is a green card with an even number or a blue card?

Answer 1

this one?

Answer 2

yea

Answer 3

k

Answer 4

its hard

Answer 5

im not sure

Answer 6

meant to post a while ago lol

Answer 7

haha

Answer 8

There are 2 green cards with even numbers and there are 5 blue cards. Therefore there are 2 + 5 = 7 cards involved in the calculation.
The probability of selecting a green card with an even number or a blue card is 7/15

Answer 9

he must be typing a lot of words

Answer 10

thanks @kropot72

Answer 11

thanks @foreverandalways13

Answer 12

what about this one?

Answer 13

A box contains 10 cards numbered 1 through 10.



Which events are mutually exclusive?

Answer 14

A.
A card is drawn from the box and the number is even.
A card is drawn from the box and the number is 4.







B.
A card is drawn from the box and the number is even.
A card is drawn from the box and the number is 2.







C.
A card is drawn from the box and the number is odd.
A card is drawn from the box and the number is 1.







D.
A card is drawn from the box and the number is even.
A card is drawn from the box and the number is 1.

Answer 15

wow they make things complicated huh?

Answer 16

very

Answer 17

lol

Answer 18

In events A, B and C it is possible that the card that is drawn first is the card that is said to be drawn next. In these cases the overall event is impossible the reason being that the sub-events cannot happen together and are therefore mutually exclusive.