Question

Help @jim_thompson5910

Answer 1

\[\sec \theta \cos \theta \]
Simplify

Answer 2

Hint:

sec(theta) = 1/cos(theta)

Answer 3

so would it be 1?

Answer 4

yep, you got it

Answer 5

Use the unit circle to find the inverse function value in degrees.\[\tan^{-1} \sqrt{3}\]

Answer 6

use this unit circle

http://3.bp.blogspot.com/-81sNFZa1qWw/UMhdT_4s7nI/AAAAAAAAAgA/oGy2QtxD8Q8/s1600/Unit+circle-tan1.JPG

the values to the right of the parenthesis are the tangent values

Answer 7

so, for example, tan(pi/4) = 1

Answer 8

since pi/4 radians = 45 degrees, we can say

tan(45) = 1

Answer 9

so would it be 120 degrees? i dont really understand this very well

Answer 10

look in the first quadrant

Answer 11

which is in the upper right

Answer 12

where do you see \(\large \sqrt{3}\) after the parenthesis ?

Answer 13

30 degrees?

Answer 14

open that image up in paint and circle it for me

Answer 15

perfect, thank you

Answer 16

what is the angle that corresponds to this point

Answer 17

30

Answer 18

the angle is off to the left of the parenthesis

Answer 19

im not sure if i understand

Answer 20

see in the parenthesis where it says 1/2, sqrt(3)/2

Answer 21

okay yeah

Answer 22

off to the left is what

Answer 23

\[\pi / 3\]

Answer 24

that's your angle in radians

Answer 25

convert that to degrees to get your answer

Answer 26

to do so, you multiply by 180/pi

Answer 27

60

Answer 28

good

Answer 29

for the next two we are trying to figure out what values for \[\theta(0\le \theta \le2\pi) \] satisfy the equation.

Answer 30

1) \[3\sin \theta = \sin \theta - 1\]
2) \[\tan^2 \theta = -3/2 \sec \theta \]

Answer 31

\[\large 3\sin \theta = \sin \theta - 1\]

\[\large 3\sin \theta - \sin \theta = - 1\]

\[\large 2\sin \theta = - 1\]

\[\large \sin\theta = -\frac{1}{2}\]

I'll let you finish

Answer 32

i dont think i got it.. i ggot 57.296

Answer 33

use the unit circle, when is sine equal to -1/2 ?

Answer 34

\[-\sqrt{3}\] ?

Answer 35

look for points that have a y coordinate of -1/2

Answer 36

then tell me the angles that correspond to these points

Answer 37

okay i figured out the answer to that one.. let me see if i can try and figure out the second one...
\[\tan^2\theta - \sec \theta = -3/2\]

is that right?