What is the 8th term of the geometric sequence -1,3,-9....?
what is your ratio?
It doesn't say, would you like me to give you the choices?
-59,049 -6,561 2,187 19,683
no,no,you have to FIND it. the radio is found by dividing the second term by the first.
Oh, forgive me. I just started to learn this.
So it would be -3
\[a_n=a_1 \times r ^{n-1}\] a(n)=the nth term a(1)=the 1st term r=common ratio
Ohhh okay. Let me explain what a geometric sequence is. a Geoemtric sequence .... ok Kaus hahaha
so we found our r=-3 and we're to find our 8th term. if we follow our formula \[\large a_{n}=a_{1}r^{n-1}\] we'll be looking for our 8th number, with this, we find it by, \[\large a_{8}=(-1)(-3)^{8-1}\]\[\large a_{8}=(-1)(-3)^{7}=2187\]
-6,561?
ARUGH
I need to study....
How did you get -6561? would you explain this to me? :P
But thank you so much!
Ill try another one on my own
Which calculus book are you using, by the way?Is it Stewart's?
I dont have a textbook, I work and take classes online.
Yeah, first find your ratio, your "a1" or first number, and then plug it into the equation to find the nth term, whatever you're looking for.
Ohh nevermind, I was going to direct you to the chapter for further study, haha.
SO this sequence is a1 = 1024 and a3=64 and I got 0.0625 Hoping thats correct? @Jhannybean
which sequence? geometric? new problem?
New problem and yes geometric, but i already check and it was correct (:
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