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Mathematics 14 Online
OpenStudy (anonymous):

help @jim_thompson5910 @jdoe0001 @Jhannybean

OpenStudy (anonymous):

OpenStudy (jhannybean):

So remember the formula \(\large y=a(x-h)^2+k\)? we're given v=(h,k)=(5,5), x=6, y=-1, we'retrying to find"a" so plugging in all of them what do you get?

OpenStudy (anonymous):

wait im confused

OpenStudy (anonymous):

how do i do that

OpenStudy (jhannybean):

plug the values in, you mean?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

howdo i find a

OpenStudy (jhannybean):

oh okay, 1) we have our vertex, which are points (h,k) represented by (5,5) according to the problem. 2) x-value = 6 3) y-value = -1 4) equation = \(\large y=a(x-h)^2+k\)

OpenStudy (jhannybean):

now we plug in ALL those values that we were given INTO \(\large y=a(x-h)^2+k\)

OpenStudy (anonymous):

ok i got that

OpenStudy (jhannybean):

\[\large \color{fuchsia}{-1}=\color{blue}a(\color{fuchsia}6-\color{fuchsia}5)+\color{fuchsia}5\] see how the "a" is blue? we're going to solve THIS equation for THAT value.\[\large -1=a(1)+5\]\[\large -1-5=a(1)\]\[\large -6= a\]

OpenStudy (jhannybean):

do you see how we solved it now by inputting ALL our givens into that equation?

OpenStudy (jhannybean):

i forgot to include the squared symbol... D:::

OpenStudy (anonymous):

yes i have 2 more is that ok

OpenStudy (jhannybean):

Use the formula i have given you and try them by yourself! :) I'm headed afk for a bit

OpenStudy (jhannybean):

You'll do fine, I believe in you!!

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

this one is toward the right what do i do?

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