help @jim_thompson5910 @jdoe0001 @Jhannybean
So remember the formula \(\large y=a(x-h)^2+k\)? we're given v=(h,k)=(5,5), x=6, y=-1, we'retrying to find"a" so plugging in all of them what do you get?
wait im confused
how do i do that
plug the values in, you mean?
yes
howdo i find a
oh okay, 1) we have our vertex, which are points (h,k) represented by (5,5) according to the problem. 2) x-value = 6 3) y-value = -1 4) equation = \(\large y=a(x-h)^2+k\)
now we plug in ALL those values that we were given INTO \(\large y=a(x-h)^2+k\)
ok i got that
\[\large \color{fuchsia}{-1}=\color{blue}a(\color{fuchsia}6-\color{fuchsia}5)+\color{fuchsia}5\] see how the "a" is blue? we're going to solve THIS equation for THAT value.\[\large -1=a(1)+5\]\[\large -1-5=a(1)\]\[\large -6= a\]
do you see how we solved it now by inputting ALL our givens into that equation?
i forgot to include the squared symbol... D:::
yes i have 2 more is that ok
Use the formula i have given you and try them by yourself! :) I'm headed afk for a bit
You'll do fine, I believe in you!!
:)
this one is toward the right what do i do?
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