Question

In need of someone with some extra time and a helpful heart! Please! Alg 2.

Answer 1

What are the possible number of positive, negative, and complex zeros of f(x)=-2x^3
Please explain

Answer 2

zeros means that f(x)= 0 and you solve for all the x's

Answer 3

Im very new at this.

Answer 4

But taking notes.

Answer 5

so to solve for the zeros

0 = -2x^3

solve for x

Answer 6

x=0

Answer 7

right,

and the "other two" zeros would just be x=0 as well

Answer 8

Oh no! I forgot to write out the whole equation , I didnt see it

Answer 9

what this means on a graph

is that the graph only crosses the x axis at zero and only zero
since its 3rd power polynomial

Answer 10

f(x)=-2x^3-5x^2-6x+4

Answer 11

So we would still be able to break it down right?

Answer 12

well, now you have to factor it

and on a side note, factoring 3rd power polynomials are not as easy to factor as 2nd power polynomials

Answer 13

oh great

Answer 14

do you know synthetic division?

Answer 15

Barely.

Answer 16

well it requires you to look at the factors of the first number and the last number

and then put it in the form of the fraction, where the last number's factor is the numerator and the first number's factor is the denominator

Answer 17

I wish I had a textbook

Answer 18

the first number is -2
the factors of -2 are -1, 1, 2 and -2

the last number is 4
the factors of 4 are 1, -1, 2, -2, 4 and -4

the possible "roots" would be 2, -2, 1, -1, 1/2, and -1/2

Answer 19

then you write the polynomial like so

Answer 20

now, we need to check which roots are possible from the possible roots

lets start with 1/2