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Mathematics 8 Online
OpenStudy (anonymous):

Can someone check my work really quick?

OpenStudy (anonymous):

Sure :)

OpenStudy (anonymous):

64^(3-x)=4^2x find the solution

OpenStudy (anonymous):

I got....

OpenStudy (anonymous):

4^3(4-x) 3(4-x)=2x 4-x=6x 4=7x x=4/7

OpenStudy (anonymous):

You're suppose to first get the 64 into 4^3. Then multiply 3(3-x)=9-x Then set 9-3x=2x

OpenStudy (anonymous):

You can find x only AFTER the bases are the same.

OpenStudy (anonymous):

I did get 4^3 into 64

OpenStudy (anonymous):

oh so mine is wrong?

OpenStudy (anonymous):

aH IN THE FIRST Q YOU WROTE (3-X) and the second (4-x) as the exponent

OpenStudy (anonymous):

One of the exponents is written wrong.

OpenStudy (anonymous):

now i confused myself

OpenStudy (anonymous):

Rewrite the actual equation. In the first problem you wrote: 64^(3-x) and then while showing your work you wrote: 4^3(4-x) Is the exponent 3-x OR 4-x at the beginning?

OpenStudy (anonymous):

3-x

OpenStudy (anonymous):

You messed up here: 4^3(3-x) 3(3-x)=2x 9-3x=2x You put 4-x instead of 3-x.

OpenStudy (anonymous):

thank you for catching that! jeez, i cant believe i did that.

OpenStudy (anonymous):

Haha no problem!!! But you know the technique good job! (:

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