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OpenStudy (anonymous):
Sure :)
OpenStudy (anonymous):
64^(3-x)=4^2x find the solution
OpenStudy (anonymous):
I got....
OpenStudy (anonymous):
4^3(4-x)
3(4-x)=2x
4-x=6x
4=7x
x=4/7
OpenStudy (anonymous):
You're suppose to first get the 64 into 4^3.
Then multiply 3(3-x)=9-x
Then set 9-3x=2x
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OpenStudy (anonymous):
You can find x only AFTER the bases are the same.
OpenStudy (anonymous):
I did get 4^3 into 64
OpenStudy (anonymous):
oh so mine is wrong?
OpenStudy (anonymous):
aH IN THE FIRST Q YOU WROTE (3-X) and the second (4-x) as the exponent
OpenStudy (anonymous):
One of the exponents is written wrong.
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OpenStudy (anonymous):
now i confused myself
OpenStudy (anonymous):
Rewrite the actual equation.
In the first problem you wrote: 64^(3-x)
and then while showing your work you wrote: 4^3(4-x)
Is the exponent 3-x OR 4-x at the beginning?
OpenStudy (anonymous):
3-x
OpenStudy (anonymous):
You messed up here:
4^3(3-x)
3(3-x)=2x
9-3x=2x
You put 4-x instead of 3-x.
OpenStudy (anonymous):
thank you for catching that! jeez, i cant believe i did that.
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OpenStudy (anonymous):
Haha no problem!!! But you know the technique good job! (: