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The charge q4 is now replaced by charge q5 which has the same magnitude, but opposite sign from q4 (i.e., q5 = -0.3 μC). What is the new value for the potential energy of the system?
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the law of electric potential energy is\[V=\frac{ 1 }{ 4 \pi \epsilon _{0} }\frac{ q }{ r }\]
potential energy of positive charge will b positive
and potential energy of negative charge will b negative
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