Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

The charge q4 is now replaced by charge q5 which has the same magnitude, but opposite sign from q4 (i.e., q5 = -0.3 μC). What is the new value for the potential energy of the system?

OpenStudy (shamim):

the law of electric potential energy is\[V=\frac{ 1 }{ 4 \pi \epsilon _{0} }\frac{ q }{ r }\]

OpenStudy (shamim):

potential energy of positive charge will b positive

OpenStudy (shamim):

and potential energy of negative charge will b negative

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!