7^x = 124 Help! I have an entire homework sheet of these things and it makes no sense to me =(
me 2 i hate homework :\
Change of base formula log124/(log7) = 2.48
a^x = b x = log(b)/loga every time.
\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]
satellite always goes Au Naturale.. only natural logs whenever he answers
ok so what happens when they give you one of these things? 3log6 (x+1) = 9
asking who?
anyone.
is it base 6?
yes
\[\log_{6} (x + 1) = 9/3 = 3\]
(x+ 1) = 6³
x+ 1 = 216; x = 215
woah! thank you! That makes sense. So the next one log(base)5 x = 3 does that become x = 3^5 x = 243 ?
ah! 5^3 nvm
Ok I'm lost again. log(base5) 2x-5 = -4
5^ -4 = 2x - 5
what?
that's not right
Whoops, mistyped...
raising the base to both sides: \[5^{\log_5(2x-5)} = 5^{-4}\]\[2x-5=\frac{1}{5^4}\]\[2x=5+\frac{1}{5^4}\]\[x=\frac{1}{2}(5+\frac{1}{5^4}) = \frac{1563}{625}\]
Instead of touching your nose straight from the front you are touching it from around your head.
Mathematician reducing everything to a previously solved problem.
\[\log_{a} B = X \space means \space a ^{X} = B\]
Different people find different explanations of equivalent statements useful.
woah gimme a sec here. I'm getting lost in a sea of numbers and letters.
ok I think I got it (thank you guys btw!) So 3 (5)^2x-3 = 6 5^2x -3 = 2 2x -3 = log2 /log 5 am I on the right track yall?
yes
then add three and divide by 2 and you are done
PRAISE JESUS!!!! I love you people. Seriously like half of my GPA is due to you guys.
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