Question

A ball is thrown upward from the top of an 80ft building so that its height in feet above the ground after t seconds is h(t)=80+64t-16tˆ2.


QUESTION: find the average velocity over the interval from t = 0 s to t = 2 s


CONFUSING.......

Answer 1

Rate of change of position is your velocity

Answer 2

Position is your height given toyou.

dh/dt will give you your average velocity

Answer 3

I mean it will give you your velocity function.

Now substitute t = 0 and you will get one value for velocity, Then put t = 2 you will get another value for velocity.

take average of the two. There is your average velocity

Answer 4

\[h(0) = 80m; h(2) = 144m\]
Time is 2 seconds.
So...
position traveled is 144-80 = 64m
time taken = 2 seconds.
Velocity is in meters per second so...
Velocity = 64/2 =

32m/s

Answer 5

thank you , I tried, and it the same answer...thxx.

Answer 6

which way did you try?

Answer 7

let 0 and 2 into the equation.
But I didnt do the substitution