A ball is thrown upward from the top of an 80ft building so that its height in feet above the ground after t seconds is h(t)=80+64t-16tˆ2.

QUESTION: find the average velocity over the interval from t = 0 s to t = 2 s

CONFUSING.......

Question

A ball is thrown upward from the top of an 80ft building so that its height in feet above the ground after t seconds is h(t)=80+64t-16tˆ2.


QUESTION: find the average velocity over the interval from t = 0 s to t = 2 s


CONFUSING.......

rajee_sam · Answer

Rate of change of position is your velocity

rajee_sam · Answer

Position is your height given toyou.

dh/dt will give you your average velocity

rajee_sam · Answer

I mean it will give you your velocity function.

Now substitute t = 0 and you will get one value for velocity, Then put t = 2 you will get another value for velocity.

take average of the two. There is your average velocity

anonymous · Answer

$$h(0) = 80m; h(2) = 144m$$
Time is 2 seconds.
So... 
position traveled is 144-80 = 64m
time taken =  2 seconds.
Velocity is in meters per second so...
Velocity = 64/2 = 

32m/s

anonymous · Answer

thank you , I tried, and it the same answer...thxx.

rajee_sam · Answer

which way did you try?

anonymous · Answer

let 0 and 2 into the equation.  
But I didnt do the substitution