y-2 = -1/3(x + 6) write in standard form using integers :)
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OpenStudy (anonymous):
please help
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Thank you c:
OpenStudy (anonymous):
is it multiple choice?
OpenStudy (anonymous):
so u can match my answer to the correct answer
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OpenStudy (anonymous):
no :/ i have to create a math textbook and i have to work out the problems
OpenStudy (anonymous):
and idk how to solve this one
OpenStudy (anonymous):
\[\frac{ x }{ 3 }+y=0\]
OpenStudy (anonymous):
one moment
OpenStudy (anonymous):
ok no problem
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OpenStudy (anonymous):
\[y-2=\frac{ -1 }{ 3}(x+6)\]
OpenStudy (anonymous):
actually the whole fraction is negative
OpenStudy (anonymous):
\[y-2=\frac{ -1 }{ 3}x-2\]
OpenStudy (anonymous):
it doesn't matter if i put the negative infront of the fraction, with the numerator, or with the denominator it still means that the fraction is negative.
OpenStudy (anonymous):
\[y=\frac{ -1 }{ 3}x\]
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OpenStudy (anonymous):
added 1/3x to both sides to get x/3+y-0 which is the equation in standard form
OpenStudy (anonymous):
im so confused as to how you went from (x + 6) to -2
OpenStudy (anonymous):
\[\frac{ x }{3 }+y=0\]
OpenStudy (anonymous):
because i had to multiply -1/3 by x to get -1/3x and then i multiplied it by 6. -1/3 times 6 = -2.
OpenStudy (anonymous):
should i draw it?
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