Which of the following is the inequality 2x + 4y < 8 when solved for y? Answer y < 8 - 2x y > 8 -2x y < 2 - 1/2 x Y < 4 - 1/2x
Ok so you need to isolate Y
how do i do that?
\[2x + 4y < 8 \]
now you subtract -2x from both sides and you get: \[4y < 8 - 2x\]
why -2x?
Well because the original equation had -2x first and you want to solve for Y not X so you move x to the other side
Now you divide 4 on both sides: \[y < 2 -2x\]
you with me so far?
yea kindda, after you finish im kindda gonna sit here and understand it all lol
xD well basically you need to get Y alone so you take away the 4 anyways moving on...
@charlieberzak It all depends on which variable (either X or Y) you're solving for, to further expand on @JA1's explanation of why you're subtracting -2x
My bad you actually divide 4 on al problems like so: 4y<8−2x /4 /4 /4 y < 2 - 1/2x
So now you get \[y < 2 - 1/2x\] Thanks @jhannybean :)
thx ja and jhanny :) now its time to sit and stare
So now just sit there and make sense of it all xD
\[2x+4y<8\]\[-2x +2x+4y < 8-2x\]\[4y < 8-2x\]\[\frac{4y}{4}< \frac{8-2x}{4}\]\[y< \frac{8}{4}-\frac{2x}{4}\]\[y< 2- \frac{x}{2}\]
haha exactly
Good luck staring :)
Nice @Jhannybean
NO i just put your explanation all together :)
yep :)
yah but yours was organized xD
Pff.
I'm so dead right now I don't know how I pulled it off xD
lol
:) cause youre smart.
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