Question

iumuikm

Answer 1

Is the denominator x^2-9?

Answer 2

Try factor x^2-9 again, you factored it wrong

Answer 3

Nope

Answer 4

\[x^2-9=(x-3)(x+3)\]

Answer 5

No, we gotta factorize it,
\[\frac{x^2-5x+6}{x^2-9}= \frac{(x-2)(x-3)}{(x-3)(x+3)}=\frac{(x-2)\cancel{(x-3)}}{\cancel{(x-3)}(x+3)}=\frac{x-2}{x+3}\]

Answer 6

Oh, from step 1 to 2, you factor both denominator and numerator, then cancel like terms from step 2 to 3, leaving x-2/x+3