Question

please help, it's trigonometry and i still am confused. equation coming

Answer 1

\[\cos(x)-\sqrt{3-3\cos^2x}=0\]

Answer 2

\(\cos x-\sqrt{3-3\cos^2x}=0\)
\(\cos x=\sqrt{3-3\cos^2x}\)
Square both sides and then solve:)

Answer 3

Does that help?

Answer 4

a little. so cos(x)*cos(x) = 3-3cos(x)?

Answer 5

cos(x)*cos(x) = 3-3cos^2(x)

Answer 6

cosx*cosx=cos^2x

Answer 7

what will be the value of cos^2x?

Answer 8

uhhhhh. i honestly do not know. i've never seen this before in my life

Answer 9

x=3-3x
can u pls solve this for x?

Answer 10

@mattishot

Answer 11

x=3-3x
0=3-3x-x = 0=3-2x, (0/3)/2 = x is undefined

Answer 12

i gotta get to my next class. thanks fo ryour help