sqrt(144) - sqrt(40) - sqrt(10) would equal Sqrt (94)? wouldn't it. or am i wrong?
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OpenStudy (anonymous):
it would not
OpenStudy (anonymous):
Can you help me figure it out then please?
OpenStudy (anonymous):
\[\sqrt{a}+\sqrt{b}\neq \sqrt{a+b}\]
OpenStudy (anonymous):
yes sure
OpenStudy (anonymous):
first off, what is the square root of 144 ?
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OpenStudy (anonymous):
The equation thing isnt working it just looks like a bunch of random letters.
OpenStudy (anonymous):
12
OpenStudy (anonymous):
refresh your browser and you should see it
yes, the square root of 144 is 12, so we can start off with
\[12-\sqrt{40}-\sqrt{10}\]
can you see that? if now i will write it out without symbols
OpenStudy (anonymous):
crashed
you still there?
OpenStudy (anonymous):
it works now.
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OpenStudy (anonymous):
whew
OpenStudy (anonymous):
haha.
OpenStudy (anonymous):
ok so now about \(\sqrt{40}\) we can write it as
\[\sqrt{40}=\sqrt{4\times 10}=\sqrt{4}\sqrt{10}=2\sqrt{10}\]
OpenStudy (anonymous):
this gives you
\[12-2\sqrt{10}-\sqrt{10}\] combine like terms, get
\[12-3\sqrt{10}\]
OpenStudy (anonymous):
okay i got that now.
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OpenStudy (anonymous):
let me know if you have any questions about any steps