Question

Please help!! How many moles of NaCl are required to prepare 2.90 L of 1.8 M NaCl?
0.62 mol NaCl
1.6 mol NaCl
4.7 mol NaCl
5.2 mol NaCl

Answer 1

Umm, I'm not too sure, but I'm thinking it's either A. 0.62 or C. 4.7... probs ask @aaronq, @.Sam. or @abb0t to check it though :)

Answer 2

Use
\[n=[M]V\]
Where
n = number of moles
[M] = concentration
V = Volume

Answer 3

lol so i guess i was totally off :P

@.Sam. it would be D. 5.2 then huh? :)

Answer 4

yep

Answer 5

haha thanks for teaching me as well!! haha :P

Answer 6

Thanks so much!

Answer 7

np:) @.Sam. is awesome haha :P i totally got the formula wrong at first lol... my bad! ;/ hehe i guess we just need to memorize that formula like @.Sam. does :P