Please help!! How many moles of NaCl are required to prepare 2.90 L of 1.8 M NaCl?
0.62 mol NaCl
1.6 mol NaCl
4.7 mol NaCl
5.2 mol NaCl

Question

anonymous · Answer

Umm, I'm not too sure, but I'm thinking it's either A. 0.62 or C. 4.7... probs ask @aaronq, @.Sam. or @abb0t to check it though :)

.sam. · Answer

Use
$$n=[M]V$$
Where
n = number of moles
[M] = concentration
V = Volume

anonymous · Answer

lol so i guess i was totally off :P

@.Sam. it would be D. 5.2 then huh? :)

.sam. · Answer

yep

anonymous · Answer

haha thanks for teaching me as well!! haha :P

anonymous · Answer

Thanks so much!

anonymous · Answer

np:) @.Sam. is awesome haha :P i totally got the formula wrong at first lol... my bad! ;/ hehe i guess we just need to memorize that formula like @.Sam. does :P