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Mathematics 19 Online
OpenStudy (anonymous):

Help with graphs please

OpenStudy (anonymous):

OpenStudy (foreverandalways13):

ok well it would be easier if both equations were in y=mx+b form...

OpenStudy (foreverandalways13):

but basically b is ur starting point on the graph and m is the slope...

OpenStudy (anonymous):

isnt the fist one in y=mx+b ithe second is y=2x+2

OpenStudy (foreverandalways13):

ok yeah so now do u know how to do the elimination method?

OpenStudy (anonymous):

um no

OpenStudy (foreverandalways13):

ok so basically what u need to do is this...|dw:1369939677302:dw|

OpenStudy (foreverandalways13):

hope that helps a little..slope though im not sure... i think u just plot that point im not sure though...do u need a line?

OpenStudy (whpalmer4):

Okay, the problem tells you to solve this by graphing, not by algebra! Bill's quick and easy graphing solution --------------------------------- Find two points for each equation. Draw straight lines through those points. Observe whether they intersect. If they intersect, the point of intersection is the solution. If they are parallel, there is no solution. If they are identical, there are infinitely many solutions. Find two points by substituting x = 0 (solve for y) and y = 0 (solve for x) into the equation. For example, y = 2x+2. Set x = 0: y = 2(0) + 2 = 4. (0,4) is the first point. Set y = 0: 0 = 2x+2. 2x = -2, x = -1. (-1,0) is the second point. Draw a straight line through the two points. Repeat for the other equation(s).

OpenStudy (foreverandalways13):

oops! sorry!

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