Question

What is the slope of a line that passes through the point (−1, 1) and is parallel to a line that passes through (4, 6) and (−1, −4)?

@sasogeek @robtobey @Hero @Hero

Answer 1

y2 - y1/x2 - x1

-4 - 6/-1 - 4 = -10/-5 = 2

So I take the 2 and plug it into y - 6 = 2(x - 4)
y - 6 = 2x - 8
y = 2x - 2

So the slope is 2, since it's parallel?

Answer 2

@Zale101

Answer 3

@reemii get ovaa here

Answer 4

yes.
Just this is enough to find the slope:
""y2 - y1/x2 - x1

-4 - 6/-1 - 4 = -10/-5 = 2 """

Answer 5

Your equation at the beginning, when you don't have any information: y = mx + p.
Now you know that m = -2. Your equation ,now: y = 2x + p.
Use the fact the hte point (-1,1) is on the line to find the value of p.

Answer 6

So wait, was I correct?

Answer 7

yes.

Answer 8

What aboot this? I'm confused.

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Answer 9

little area / big area

Answer 10

x/x+5 = 4x/ x^2 + 7x + 10

Answer 11

little area: x(x+5).
big area: (x^2+7x+10) * 4x
there is a factorization that you can do with the polynomial x^2+7x+10.

Answer 12

x(x+ 5)/(x + 5)(x + 2) = x/x + 2

Answer 13

yes. since there's also a "4x" factor, you get the second proposition.

Answer 14

H-huh?