Question

I Need Some Help Please!
The polygons are similar, but not necessarily drawn to scale. Find the value of x.

Answer 1

@Juarismi can u help me?

Answer 2

Well, similarity means that the corresponding sides asre proportional, so consider
x/3 = 40/12
Then solve for x.

Answer 3

@Juarismi so i cross multiply?

Answer 4

Yes , cross multiply

Answer 5

so i would do x*12 = 3*40

Answer 6

Yes, now divide both sides by 12, and simplify.

Answer 7

120/12 = 10

Answer 8

Correct, that's the answer!

Answer 9

Thank you!

Answer 10

Hey you think you could help me with some more?

Answer 11

I can try.

Answer 12

State whether the triangle are similar. If so, write a similarity statement and the postulate or theorem you used.

Answer 13

The triangles KOJ and NOM are similar because thay have one corresponding angle congruent (<KOJ = <NOM) and because the corresponding sides are in the same proportion
OM/OJ = 32/24 = 4/3
ON/OK = 24/18 = 4/3.

Answer 14

Thank you again!

Answer 15

@Juarismi so i would be using SAS?

Answer 16

Yes , is SAS

Answer 17

Okay

Answer 18

Which theorem or postulate proves the two triangles are similar? The figure is not drawn to scale.

Answer 19

@Juarismi

Answer 20

The arrow on each line means that they are parallel, so by the property of parallel lines, the three pairs of corresponding angles are the same. And that's AAA similarity.

Answer 21

AAA isnt one of my choices tho.

Answer 22

is it AA?

Answer 23

@Juarismi

Answer 24

Well if AA is one of the choices, it must be correct

Answer 25

DO you know how to find the geometric mean of pair numbers?

Answer 26

@Juarismi

Answer 27

The formula for geometric mean of n numbers is:
\[\sqrt[n]{a_1a_2a_3..a_n}\]

Answer 28

ok the numbers are 99 and 11 @Juarismi

Answer 29

So the geom. mean will be:
\[\sqrt{99*11}=\sqrt{1089}=33\]

Answer 30

Thank you, you are sooo helpful!

Answer 31

Welcome

Answer 32

What is the value of x, given that OP||NQ ?

Answer 33

@Juarismi

Answer 34

\[\frac{ 18+9 }{ 18 }=\frac{ 20+x }{ 20 }\]
Solve for x

Answer 35

now how exactly do i do that? @Juarismi

Answer 36

\[\frac{ 27 }{ 18 }=\frac{ 20+x }{ 20 }\]
\[\frac{ 3 }{ 2}=\frac{ 20+x }{ 20 }\]
\[60=40+2x\]
\[2x=20\]
\[x=10\]

Answer 37

In triangle ABC, <A is a right angle, and m<B= 45 degrees. Find BC. If your answer is not an integer, leave it in simplest radical form.

Answer 38

@Juarismi

Answer 39

Because <B is 45, then <C is also 45 (cause B and C must add up to 90)
Therefore ABC is an isosceles triangle where AB=AC=11.
Now we use the pythagorean theorem and:
(AC)^2+(AB)^2 = (BC)^2
11^2 + 11^2 = (BC)^2
Then solve for BC.

Answer 40

so.. it would be 22?

Answer 41

@Juarismi

Answer 42

\[11^2+11^2=(BC)^2\]
\[242=(BC)^2\]
\[BC=\sqrt{242}\]
\[11\sqrt{2}\]

Answer 43

Oh ok thanks

Answer 44

The length of the hypotenuse of a 30degree -60degree -90degree triangle is 7. Find the perimeter

Answer 45

@Juarismi

Answer 46

The 30-60-90 degrees triangle satisfy always the following:



So in this case 2a=7, so just find a and then add all them .

Answer 47

so would it be \[\frac{ 21 }{2 } + \frac{ 7 }{ 2 } \sqrt{3}\]

Answer 48

@Juarismi

Answer 49

Yes, thats correct.

Answer 50

YAY!

Answer 51

Find the missing value to the nearest hundredth . tan ____ = 7

Answer 52

@Juarismi

Answer 53

The missing value is just the arctan(7)

Answer 54

@Juarismi so it would be 81.87

Answer 55

Yes , it's 81.87

Answer 56

Write the ratios for sin A and cos A.

Answer 57

Sin A = opposite/hipotenuse = 15/17
Cos A = adyacent/hipotenuse = 8/17

Answer 58

Im glad i asked you this one, cuz i had 8/17 15/17