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Suppose the probability that it rains in the next two days are 1/3 for tomorrow and 1/6 for the day after tomorrow. What is p( rain tomorrow then rain the day after tomorrow ? 1/2 1/18 2/9 1/9 Show your work
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The required probability is the product of the two values of probability that are given.
how do you do that?
@kropot72
\[P(rains\ both\ days)=\frac{1}{3}\times \frac{1}{6}=\ ?\]
2/18
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@kropot72
\[\frac{1}{3}\times \frac{1}{6}=\frac{1\times 1}{3\times 6}=\ ?\]
1/18
1/18 is correct :)
thank you :)
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You're welcome :)
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