HELP PLEASE MEDAL AND FAN REWARDED!!

Question

anonymous · Answer

attachment

andriod09 · Answer

Hey Divagirl! The first thing you should do is take away those nasty parenthesis by distributing the 2 by the x, and change the x-(-4) into x+(+4) and then distribute, like so: $$y=2(x-(-4))^2+(-7)$$$$y=(2x+(+4))^2+(-7)$$ that way you can solve it by there, by taking the square, and making the equation into $$y=4x^2+4x+8$$ Hope I helped you! Have fun!

anonymous · Answer

thanks alot:)

anonymous · Answer

thats incorrect

andriod09 · Answer

:O what? I triple checked my math though. >.< hold on, let me get someone who's a bit better than me to help.

anonymous · Answer

i have another question maybe you can help with that

andriod09 · Answer

@amistre64 help us pl0x? Is this a test? Or a quiz?

anonymous · Answer

practice

anonymous · Answer

attachment

anonymous · Answer

@Hero  @mathstudent55

amistre64 · Answer

if you insist on distributing thru a (...)^n  , you must first adjust that 2 so that it equates inside the power:

$$2=(\sqrt2)^2$$
so youd actually be distributing a sqrt(2) inside of the (...)^2

amistre64 · Answer

it tends to be best just to expand the power grouping first, then multiply it all by 2