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Mathematics 16 Online
OpenStudy (anonymous):

Which inequality matches the graph below? (Graph Attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

Choices: y > |x + 2| + 1 y < |x – 2| + 1 y < |x + 2| – 1 y > |x – 2| – 1

OpenStudy (johnweldon1993):

Well, what kind of functions act like that when graphed?

OpenStudy (johnweldon1993):

lol nvm....all the answer choices show that it is an absolute value function lol....so how would you go about solving this?

OpenStudy (anonymous):

I've been trying to find that out, i don't have any examples in my notes :/

OpenStudy (johnweldon1993):

Well we can begin to eliminate 2 of the answers...is this a GREATER THAN function...or a LESS THAN function?

OpenStudy (anonymous):

How do i determine that?

OpenStudy (johnweldon1993):

The easiest way is...look at the graph....is the point (0,0) in the shaded area?

OpenStudy (anonymous):

Yes

OpenStudy (johnweldon1993):

So you can take one of each (Greater than, less than) equations in your answer choices....and plug in 0 for 'y' a 0 for 'x' so lets look at answer choices A and B y > |x + 2| + 1 0 > |0 + 2| + 1 0 > |2| + 1 0 > 3 NO....this is NOT a GREATER THAN function y < |x – 2| + 1 0 < |0 - 2| + 1 0 < |-2| + 1 0 < 2 + 1 0 < 3 YES....this IS a LESS THAN function So...now you can eliminate answer choices A and D right?

OpenStudy (anonymous):

So if the origin of the graph is in the shaded area then it is a less than function?

OpenStudy (anonymous):

@johnweldon1993 ?

OpenStudy (johnweldon1993):

not in all examples no...don't make that assumption.....just a way to check. so now... if you add a 1 to a function...that shifts the graph UP above the origin by 1 correct? ...well this is BELOW the origin...so it must be subtracting 1...what choice are we left with?

OpenStudy (anonymous):

B?

OpenStudy (johnweldon1993):

no B is the one where you add 1 to a function....here I'll do a visual for you ...makes it easier to understand

OpenStudy (johnweldon1993):

|dw:1369942778007:dw|

OpenStudy (johnweldon1993):

now if you add 1 to that function....you move that graph UP 1 unit ... if you SUBTRACT 1 from that function....you move that graph DOWN 1 unit.....the answer would be C right?

OpenStudy (johnweldon1993):

|dw:1369942898389:dw|

OpenStudy (johnweldon1993):

|dw:1369942926252:dw|

OpenStudy (anonymous):

Ah yes, i understand now. Visuals help lol

OpenStudy (johnweldon1993):

haha no problem!

OpenStudy (anonymous):

Can i ask if i have gotten this right?

OpenStudy (anonymous):

I got

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (johnweldon1993):

Can I guess that 1 of the answer choices is \[x ^{13/5}\]

OpenStudy (anonymous):

The choices are: x 1/5 x 14/15 x 1/2 x 5/9 @johnweldon1993

OpenStudy (anonymous):

Nvm those are the wrong ones.

OpenStudy (anonymous):

There is a 13/5 though.

OpenStudy (johnweldon1993):

lol I was just going to say...that's very odd haha....when you multiply exponents with the same bases......you add the exponents

OpenStudy (johnweldon1993):

I'm curious as to how you got 6/5 however...can you show me what you did?

OpenStudy (anonymous):

I simplified the fractions. So 12 went to 6 and 10 went to 5 :p

OpenStudy (johnweldon1993):

\[x ^{3/5} x ^{4/2}\] this becomes \[x ^{\frac{ 3 }{ 5 } + \frac{ 4 }{ 2 }}\] from there you find the least common denominator which is 10 here so 6 20 -- + --- 10 10 26 --- 10 simplify that into 13 --- 5 and raise 'x' to that power x ^ (13/5) :)

OpenStudy (anonymous):

Thanks again!

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