Which inequality matches the graph below? (Graph Attached)
Choices: y > |x + 2| + 1 y < |x – 2| + 1 y < |x + 2| – 1 y > |x – 2| – 1
Well, what kind of functions act like that when graphed?
lol nvm....all the answer choices show that it is an absolute value function lol....so how would you go about solving this?
I've been trying to find that out, i don't have any examples in my notes :/
Well we can begin to eliminate 2 of the answers...is this a GREATER THAN function...or a LESS THAN function?
How do i determine that?
The easiest way is...look at the graph....is the point (0,0) in the shaded area?
Yes
So you can take one of each (Greater than, less than) equations in your answer choices....and plug in 0 for 'y' a 0 for 'x' so lets look at answer choices A and B y > |x + 2| + 1 0 > |0 + 2| + 1 0 > |2| + 1 0 > 3 NO....this is NOT a GREATER THAN function y < |x – 2| + 1 0 < |0 - 2| + 1 0 < |-2| + 1 0 < 2 + 1 0 < 3 YES....this IS a LESS THAN function So...now you can eliminate answer choices A and D right?
So if the origin of the graph is in the shaded area then it is a less than function?
@johnweldon1993 ?
not in all examples no...don't make that assumption.....just a way to check. so now... if you add a 1 to a function...that shifts the graph UP above the origin by 1 correct? ...well this is BELOW the origin...so it must be subtracting 1...what choice are we left with?
B?
no B is the one where you add 1 to a function....here I'll do a visual for you ...makes it easier to understand
|dw:1369942778007:dw|
now if you add 1 to that function....you move that graph UP 1 unit ... if you SUBTRACT 1 from that function....you move that graph DOWN 1 unit.....the answer would be C right?
|dw:1369942898389:dw|
|dw:1369942926252:dw|
Ah yes, i understand now. Visuals help lol
haha no problem!
Can i ask if i have gotten this right?
I got
@johnweldon1993
Can I guess that 1 of the answer choices is \[x ^{13/5}\]
The choices are: x 1/5 x 14/15 x 1/2 x 5/9 @johnweldon1993
Nvm those are the wrong ones.
There is a 13/5 though.
lol I was just going to say...that's very odd haha....when you multiply exponents with the same bases......you add the exponents
I'm curious as to how you got 6/5 however...can you show me what you did?
I simplified the fractions. So 12 went to 6 and 10 went to 5 :p
\[x ^{3/5} x ^{4/2}\] this becomes \[x ^{\frac{ 3 }{ 5 } + \frac{ 4 }{ 2 }}\] from there you find the least common denominator which is 10 here so 6 20 -- + --- 10 10 26 --- 10 simplify that into 13 --- 5 and raise 'x' to that power x ^ (13/5) :)
Thanks again!
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