What is the theoretical probability of being dealt exactly two 2's in a 5-card hand from a standard 52-card deck?

Question

anonymous · Answer

Can someone explain how to solve this?

anonymous · Answer

two "2" and 3 "not 2" you can use 
$$\frac{\binom{4}{2}\binom{48}{3}}{\binom{52}{5}}$$

anonymous · Answer

that is, the number of ways you can choose 2 out of the 4 twos time the number of ways to choose  3 out of the 48 other cards, divided by the total number of ways you can choose 5 out of the 52 cards

anonymous · Answer

I'm sorry but I still don't understand...

anonymous · Answer

do you know what i meant by $\binom{48}{3}$?  you may have seen this written instead as $_{48}C_3$

anonymous · Answer

ah! Yeah, I know what that is! haha now that makes sense.

anonymous · Answer

good

anonymous · Answer

If it's two of 2's where did 4C2 come from? Shouldn't it be 2C2?

anonymous · Answer

there are 4 "2's" in the deck, you want to choose two of them

anonymous · Answer

ah ok

anonymous · Answer

So is the answer 2162/54145?