(5+√11)(5-√11) Please help i give medals! Answer choices: A.36 B.14 C.25-10√11 D.25-√11
Hint: \(x^2 - y^2 = (x+y)(x-y)\)
What formula is that called? It's not the quadratic one is it?
It's the difference of two squares identity.
ugghh I'm not sure how to do that
Just observe the formula and fill in the blanks. What would x and y stand for in the case of \((5+\sqrt{11})(5-\sqrt{11})\)?
x would be 5 and y would be sqrt11, im not sure though. (sorry it took me so long to rrespond my computer shut down for an update and i had to switch to another computer.
Correct. Now apply that to \(x^2 - y^2\)
X would be 25 i think and if you squared a radical sign it should cancel leaving 11.
im not sure though
Correct.
However, x^2 = 25, not x = 25.
so thats the answer?
D
No. x = 5, y = sqrt(11) x^2 = 25, y = 11 We know that x^2 - y^2 = (x+y)(x-y) So what is x^2 - y^2?
25-11=14
or do you have to square the 11 to?
No. It's asking y^2, not y.
so 121?
d because 11 cant be broken down and 5*5 is 25
@callie2240 Please read my solution. @csimmons3 You must be very clear of what you are doing here. Back to first step: You defined x = 5 and y = sqrt(11), this doesn't change for the whole progress. The answer is x^2 - y^2, so you find x^2 and y^2 and substitute them into the equation. You don't magically transform y^2 into y - they stay two different (but related) numbers.
*substitute into the expression
i dont see a solution???
I'm lost
Ohhhh is it B?
Correct. Next time you do math, in order to make yourself very clear about what you're doing, write variables and their values out. This way, you won't be confused. @callie2240 See all my posts for details.
Thanks for all the help :)
i saw thanks
it would be B
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