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How do I solve this using substitution? x squared + y squared = 13 2x - y = 4
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first solve the second equation for y 2x - y = 4 -y = 4-2x y = -4 + 2x y = 2x - 4 Then plug this into the first equation x^2 + y^2 = 13 x^2 + (2x-4)^2 = 13 x^2 + 4x^2 - 16x + 16 = 13 I'll let you finish
Would x = 3\11?
Or never mind...that's not right
x = 3 and 1\5
yes, x = 3 or x = 1/5 are your two solutions for x use them to find the corresponding values of y
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y = -18\5 and 2
so what are the two ordered pairs
(3,2) and (1\5, -18\5)
very good again remember the slashes go the opposite way, but you got it pretty much
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