(3/x-3) - (5/x-2)
\(\Huge{\color{purple}{\textbf{W}} \color{orange}{\cal{E}} \color{green}{\mathbb{L}} \color{blue}{\mathsf{C}} \color{maroon}{\rm{O}} \color{red}{\tt{M}} \color{gold}{\tt{E}} \space \color{orchid}{\mathbf{T}} \color{Navy}{\mathsf{O}} \space \color{OrangeRed}{\boldsymbol{O}} \color{Olive}{\mathbf{P}} \color{Lime}{\textbf{E}} \color{DarkOrchid}{\mathsf{N}} \color{Tan}{\mathtt{S}} \color{magenta}{\mathbb{T}} \color{goldenrod}{\mathsf{U}} \color{ForestGreen}{\textbf{D}} \color{Salmon}{\mathsf{Y}} \ddot \smile }\) \[\frac{ 3 }{ 3 - x } - \frac{ 5 }{ x - 2}\] Do you know the first step?
no
First fine the lowest common denominator between 3 - x and x - 2 You'll see that the lowest denominator is 6. I need to multiply 3 - x by 2 and x - 2 by 3. Remember, when I multiply the denominator I must also do it to the numerator to keep equality. \[\frac{ 2(3) }{ 2(3 - x) } - \frac{ 3(5) }{ 3(x - 2) } \rightarrow \frac{ 6 }{ 6 - 2x} - \frac{ 15 }{3x - 6 ? }\]
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