Question

simplify this pleaseeee

Answer 1

\[\frac{ x^2 }{ x^2-9y^2 }*\frac{ 2x }{ x+3y }\]

Answer 2

Just multiply numerators together and denominators together.

Answer 3

Like this: \[\Large\cdots = \dfrac{(x^2)(2x)}{(x^2 - 9y^2)(x+3y)}\]

Answer 4

thanks a lot!

Answer 5

No problem

Answer 6

do terms have to have the same degree to combine? like 3(x^2)y and 9x(y^2)?

Answer 7

Well, you can just leave it like 3x²y and 9xy².
That's all you can do.

Answer 8

okay. sounds good

Answer 9

wait a sec..my answer i got was 2/3y(x^2-3xy-9y^2), but this is the question on the quiz:

Answer 10

Oh ah, it actually reduced to \(\dfrac{(x^2)(x+3y)}{(x^2-9y)(2x)}\)

Answer 11

:/ i'm just bad at math lol

Answer 12

And You can factor \(x^2 - 9y^2\) which is equal to \((x+3y)(x-3y)\)

Answer 13

So it equal \(\dfrac{(x^2)(x+3y)}{(x-3y)(x+3y)(2x)}\)

Answer 14

So x+3y is canceled.

Answer 15

i follow you. then x^2 goes down to x and 2x goes to 2, right?

Answer 16

Yes!

Answer 17

thankks :) i appreciate it

Answer 18

No problem :)