Question

Find the limit of the function algebraically.



Does not exist

8

0

-8

Answer 1

There is no limit it

Answer 2

thats what i am thinking too

Answer 3

It doesn't exist

Answer 4

\[\large \lim_{x \rightarrow 0}\frac{ x^2-2x }{ x^4 }\]\[\large \lim_{x \rightarrow 0}\frac{ x(x-2) }{ x^4 }\]\[\large \lim_{x \rightarrow 0}\frac{ (x-2) }{ x^3 }\] since that's teh least you can factor it, you take the limit. \[\lim_{x \rightarrow 0}\frac{ (0-2) }{ 0^3 }= \frac{ -2 }{ 0 }=0\]

Answer 5

Therefore the limit is 0.

Answer 6

Thats the most you can factor it *

Answer 7

Actually the limit DNE

Answer 8

oh haha nevermind, yes,, the limit does not exist :| sorry...

Answer 9

it's only 0 if it's 0/1 or 0 in the numerator specifically. :|

Answer 10

good job Luigi.

Answer 11

I try :D