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OpenStudy (anonymous):
ind all of the solutions for the following equation.
tan(x) = 4 tan (x) - (sqrt)(3)
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OpenStudy (anonymous):
\[\tan(x)=4\tan(x)-\sqrt{3}\]
OpenStudy (tkhunny):
Have you considered solving \(3\tan(x) = \sqrt{3}\)?
OpenStudy (anonymous):
I have not. is that the thing i need?
OpenStudy (tkhunny):
If you subtract \(\tan(x)\) from both sides and add \(\sqrt{3}\) to both sides, that is where you end up. What's next?
OpenStudy (anonymous):
Uhhh. divide each side by 3.
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OpenStudy (tkhunny):
Right. Where does that lead us?
OpenStudy (anonymous):
\[\tan(x)=\frac{ \sqrt{3} }{ 3 }\]
OpenStudy (tkhunny):
...or \(\dfrac{1}{\sqrt{3}}\)
OpenStudy (anonymous):
here's the question with answers:
so 1/root3. is that the solution then?? bc that's equal to a certain degreee, right?
OpenStudy (tkhunny):
We have \(\tan(x) = \dfrac{1}{\sqrt{3}}\)
We still need \(x = ??\).
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OpenStudy (anonymous):
inverse tangent of 1/root3
OpenStudy (anonymous):
x = 30
OpenStudy (anonymous):
now how do i know if it's 30 + 180 or 30 + 360?
OpenStudy (tkhunny):
\(... + k\cdot 180º\)
OpenStudy (anonymous):
lol. ok then. thank you very very much :)
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