ind all of the solutions for the following equation. tan(x) = 4 tan (x) - (sqrt)(3)
\[\tan(x)=4\tan(x)-\sqrt{3}\]
Have you considered solving \(3\tan(x) = \sqrt{3}\)?
I have not. is that the thing i need?
If you subtract \(\tan(x)\) from both sides and add \(\sqrt{3}\) to both sides, that is where you end up. What's next?
Uhhh. divide each side by 3.
Right. Where does that lead us?
\[\tan(x)=\frac{ \sqrt{3} }{ 3 }\]
...or \(\dfrac{1}{\sqrt{3}}\)
here's the question with answers: so 1/root3. is that the solution then?? bc that's equal to a certain degreee, right?
We have \(\tan(x) = \dfrac{1}{\sqrt{3}}\) We still need \(x = ??\).
inverse tangent of 1/root3
x = 30
now how do i know if it's 30 + 180 or 30 + 360?
\(... + k\cdot 180º\)
lol. ok then. thank you very very much :)
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