Question

In a closed system, Glider A with a mass of 0.40 kg and a speed of 4.00 m/s collides with Glider B at rest with a mass of 0.40 kg. The two interlock and move off. What speed are they moving?

0.50 m/s

1.0 m/s

2.0 m/s

4.0 m/s

Answer 1

So you have an system that looks like

\[M _{glider1}^{}V _{glider1(initial)}^{} + M _{glider2}^{}V _{glider2(initial)}^{} = (M _{glider1}^{} + M _{glider2}^{})V _{gliders(final)}^{} \]

They have the same velocity at the end because they are interlocked

So Rearrange for V_final....plug in all your numbers and solve

Answer 2

okay

Answer 3

so 0.40 + 0.40?

Answer 4

4.0
?

Answer 5

not quite

when you plug the numbers in *after rearranging for V_final you should have

Mass of glider 1...times velocity (initially) of glider 1......ALL DIVIDED BY (Mass of glider1 + Mass of glider2)

Answer 6

ooh

4.4

Answer 7

is what i got

Answer 8

it should be

.40kg Times 4.00m/s
-------------------
(.40kg + .40kg)

what does this equal?

Answer 9

2

Answer 10

great!

Answer 11

another question

Answer 12

A shot-putter throws a 5.0 kg shot at a speed of 10.0 m/s. What is the kinetic energy of the shot?

Answer 13

\[Kinetic Energy = \frac{ 1 }{ 2 } m v^2\]