Question

Solve 6^(2x) > 5^(x + 2).

Answer 1

2xlog6>(x+2)log5
/log5 /log5
2.23x>x+2
-x -x
1.63x>2
x>1.23

Answer 2

thats what i think the answer is

Answer 3

the 4 answeres are x>1.83 x>1.63, x>.85, or x>.82 :(

Answer 4

lol 4 answers wdh

Answer 5

that doesnt make sense

Answer 6

it's multiple choice :/

Answer 7

so answer is x>1.63

Answer 8

i see you had 1.63x, and if you divide 1.63 by 2 you get .815 which roudns up to .82

Answer 9

but 1.63 and x are on the same side so nvm that

Answer 10

oops yeah, this stupid windows calc sucks

Answer 11

jhanny prob has right answer

Answer 12

jhanny stopped typing :3

Answer 13

well the answer is 1.63
i accently put that 2.23-1=1.63 but it equals 1.23

Answer 14

so 2/1.23 = 1.63

Answer 15

ohhhh okay

Answer 16

again, stupid calc

Answer 17

i shouldve used my real life one

Answer 18

hehe

Answer 19

\[\large 6^{(2x)}> 5^{(x+2)}\]\[\large \ln(6)^{(2x)}> \ln5^{(x+2)}\]\[(2x)*\ln(6)> (x+2)*\ln(5)\]\[2x*\ln(6)>x*\ln(5)+2*\ln(5)\]\[2x*\ln(6)-x*\ln(5)> 2*\ln(5)\]

Answer 20

Soo...i'm needing some help.. haha.

Answer 21

ewwwwwwww i need a pen for this

Answer 22

Lol I think we got the right answer, jhanny :p

Answer 23

wow she went nerd rage using nat log :OO, but regular log is best

Answer 24

easier imo

Answer 25

Or wait... \\[x(2\ln(6)-\ln(5))>2\ln(5)\]\[\frac{ 2(\ln(6)) }{ \ln(5) }> \frac{ 2\ln(5) }{ x }\]\[\frac{ 1 }{ 2\ln(5) }*\frac{ 2\ln(6) }{ \ln(5) }> \frac{ 1 }{ x }\]

Answer 26

Yeah i'm done...... lol i don't even know what i'm doing anymore.

Answer 27

lol

Answer 28

yeah that is way off i think

Answer 29

what was your answer choices?

Answer 30

he had i see you had 1.63x, and if you divide 1.63 by 2 you get .815 which roudns up to .82

Answer 31

lol lolol

Answer 32

You guys wanna give a whirl to this one?

Answer 33

It's the last question in my test :3 idk how to do it

Answer 34

who me?

Answer 35

yessss sir. you seem to have a good head on your shoulders.

Answer 36

jhanny can take this one :P ill try it tho

Answer 37

not to rush, but there's 6 mins left ont he test :3

Answer 38

wait a minute,you're taking a test right now and asking us questions? Wth.

Answer 39

it's online.

Answer 40

unsupervised

Answer 41

That is not allowed on Openstudy. Sorry.

Answer 42

wow someone is mad

Answer 43

That is called cheating, whether online OR offline.

Answer 44

take it easy jhanny

Answer 45

Follow the rules of conduct for this site please.

Answer 46

okok i'll just go guess. take a chill pill :3

Answer 47

i think answer is 0.101

Answer 48

or 0.01

Answer 49

yeah i guessed that. just quick did it on my calculator.

Answer 50

i mean 0.1 which is d

Answer 51

final on my last exam: 76% :))

Answer 52

Alexis, can you stop giving him answers, if he's doing a test,let him finish his test, then the person can come get answers,or help.

Answer 53

ok soz, btw if he cheats its his problem, i give answers to all cheaters or not

Answer 54

its his choice, let him not learn or learn at will

Answer 55

But you're not going to feed him answers for a test he's currently taking, that's breaking OpenStudy rules. How can you contribute to that? I don't understand.

Answer 56

well rules are rules, i did not read them and i shall not read them, but if you say so i shall stop

Answer 57

well test is over and i'l never need this site again <3 it's been a good run, everybody :) can't say i'll miss doing math

thanks for the help alexis!

Answer 58

Ridiculous.

Answer 59

ahaha ok gl mattishot

Answer 60

yeah you too :)