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OpenStudy (anonymous):
verify the identity:
sin(π/2+x)=cosx
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OpenStudy (zzr0ck3r):
sin ( pi/2 + x ) = sin(pi/2)cos(x) + cos(pi/2)sin(x) = 1*cos(x) + 0
OpenStudy (anonymous):
how did you get to that point?
OpenStudy (zzr0ck3r):
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
OpenStudy (anonymous):
Addition identities. They're pretty great.
OpenStudy (zzr0ck3r):
sin(A+B)=sin A cos B + cos A sin B
sin(A-B)=sin A cos B - cos A sin B
cos(A+B)=cos A cos B - sin A sin B
cos(A-B)=cos A cos B + sin A sin B
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OpenStudy (anonymous):
oh yes, i remember those formulas! thanks for the refresher ;)
OpenStudy (zzr0ck3r):
np, I don't remember them I google them:)
OpenStudy (zzr0ck3r):
well ok sin(a+b) I remembered..
OpenStudy (anonymous):
hahaha @zzr0ck3r ok, thanks anyways
OpenStudy (anonymous):
\[\sin{\pi\over2}\cos x+\cos{\pi\over2}\sin x\]\[(1)(\cos x)+0(\sin x)\]\[\cos x+0\]\[\sin({\pi\over2}+x)=\cos x\]
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OpenStudy (zzr0ck3r):
np
OpenStudy (zzr0ck3r):
that's pretty:)
OpenStudy (anonymous):
what is? lol
OpenStudy (anonymous):
i have no idea..maybe your beautiful math response...its neatly typed haha
OpenStudy (anonymous):
lol, hope i've been helpful! :)
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OpenStudy (anonymous):
yes, thanks! @yummydum
OpenStudy (anonymous):
Anytime! :)
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