verify the identity: sin(π/2+x)=cosx
sin ( pi/2 + x ) = sin(pi/2)cos(x) + cos(pi/2)sin(x) = 1*cos(x) + 0
how did you get to that point?
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
Addition identities. They're pretty great.
sin(A+B)=sin A cos B + cos A sin B sin(A-B)=sin A cos B - cos A sin B cos(A+B)=cos A cos B - sin A sin B cos(A-B)=cos A cos B + sin A sin B
oh yes, i remember those formulas! thanks for the refresher ;)
np, I don't remember them I google them:)
well ok sin(a+b) I remembered..
hahaha @zzr0ck3r ok, thanks anyways
\[\sin{\pi\over2}\cos x+\cos{\pi\over2}\sin x\]\[(1)(\cos x)+0(\sin x)\]\[\cos x+0\]\[\sin({\pi\over2}+x)=\cos x\]
np
that's pretty:)
what is? lol
i have no idea..maybe your beautiful math response...its neatly typed haha
lol, hope i've been helpful! :)
yes, thanks! @yummydum
Anytime! :)
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