Question

@johnweldon1993 are you good at these???
Isabel bought a desktop computer and a laptop computer. Before finance charges, the laptop cost 250 more than the desktop. She paid for the computers using two different financing plans. For the desktop the interest rate was 8.5% per year, and for the laptop it was 5% per year. The total finance charges for one year were 296 . How much did each computer cost before finance charges?

Answer 1

I'm trying to do it out hang on :)

Answer 2

Ha yes got it...okay ready? you'll be doing the work :)

Answer 3

*p.s It's just another system of equations...as you'll see*

Answer 4

So step 1...have you gotten any equations written down from this information?

Answer 5

i figured it out but i cant figure out this one


A theater group made appearances in two cities. The hotel charge before tax in the second city was 1500 higher than in the first. The tax in the first city was 5% , and the tax in the second city was 7.5% . The total hotel tax paid for the two cities was $737.5 . How much was the hotel charge in each city before tax?

Answer 6

haha aww after all that work :P and this would be the same exact process as that computer one...

Answer 7

okayy so y=x+1500 and 0.05x+0.75(x+1500)=737.5 ????

Answer 8

exactly

Answer 9

well no...not EXACTLY!!! lol....what is 7.5% in decimal form?

Answer 10

.75????

Answer 11

you had it right with 5%.....you move the DECIMAL place over 2 to the left right?

Just like in the computer problem...with the 8.5%...would be .085

Answer 12

ohhh okay so its .875x=625??

Answer 13

woh....where did THOSE numbers come from?

you have *with corrected percent

"okayy so y=x+1500 and 0.05x+0.075(x+1500)=737.5 ????"

Answer 14

i caught that lol so its 0.125x=625??

Answer 15

so x = 5000 and y = 6000

Answer 16

Looks correct to me :) as long as you checked them

Answer 17

WAIT! no! lol...check them!!!

Answer 18

i did!!!! lol is this the same way or different set up??
Henry bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $200 less than the desktop. He paid for the computers using two different financing plans. For the desktop the interest rate was 5% per year, and for the laptop it was 7% per year. The total finance charges for one year were $250 . How much did each computer cost before finance charges?

Answer 19

"the second city was 1500 higher than in the first" YOU CHECKED THEM AND IT WORKED!?

Answer 20

yeah and it was right lol

Answer 21

you used 5000 for x and 6000 for y???

Answer 22

yeah lol

Answer 23

lmao please check it again! xD I'm so confused! haha

Answer 24

6500 because 5000+1500=6500

Answer 25

HA! yes there we go! lol....you said 6000 before! haha

Answer 26

oh stupid keyboard lol can u help with the new one??? lol and 1 more of this kind after

Answer 27

and this previous one you posted SAME THING...just remember "the laptop cost $200 less than the desktop"

Answer 28

so y =200-x??

Answer 29

correct!

Answer 30

and 0.05x-0.07y=250

Answer 31

so y =200-x??
should be
y = x - 200...but yes...and yes on the percents

Answer 32

so then is 0.05x+0.07x-14=250??

Answer 33

and 0.05x "+" 0.07y=250

Answer 34

so then x=2200 and y = 2200-200 so y =2000

Answer 35

and check themmmmm lol *going to be my catch phrase :D

Answer 36

lol i did and they were right :D
you make this easy

Answer 37

We'll You're making it Easy lol...you're doing all the work :D

Answer 38

you are helping lol okay last one of this kind...

Last year, Chris had 10,000 to invest. He invested some of it in an account that paid simple 7% interest per year, and he invested the rest in an account that paid simple 5% interest per year. After one year, he received a total of $560 in interest. How much did he invest in each account?

Answer 39

y=10,000-x and 0.07x+0.05y=560???

Answer 40

I'm going to let you do this one...you've surpassed my teaching :D

Answer 41

x=3000 and y =7000??

Answer 42

Bravo! :)

Answer 43

i checked and they were right!!!!!

Answer 44

r u good at these



Two buses leave towns 616mi apart at the same time and travel toward each other. One bus travels 8mi/h slower than the other. If they meet in 4 hours, what is the rate of each bus?

Answer 45

Pretty much still system of equations

They meet in 4 hours...so 4x would represent the distance covered by the faster car here.

So bus 1....travels 8mi/h slower....

x - 8 is the rate of bus 1

4(x-8) would be the rate of the slower car

They are 616 mi apart so

4(x - 8) + 4x = 616

And solve :)

Answer 46

*sorry didn't really know how to explain it...so I did some of it lol

Answer 47

x=81 so where do i plug it in at

Answer 48

so rate one is 73 and the other is 292??

Answer 49

This is the rate of the faster car here....so the slower car would be that - 8

Answer 50

so if the faster car is 81-8 its 73 so the other one is 4(73) so 292

Answer 51

so faster car rate is 81 and slower car rate is 81 - 8 = 73

and we can check by

4(x) + 4(y) = 616
4(81) + 4(73) = 616

Answer 52

*what you're doing...is solving how far the cars are going...they are asking for the rates only

Answer 53

buses*

Answer 54

ohh i see

Answer 55

I feel like that one confused you??

Answer 56

it did but it was right lol

Answer 57

Because I can probably make it easier to follow if I added another variable if you want?

Answer 58

nope i got it lol

Answer 59

Okay, but I can :) lol

Answer 60

lol if i need help with my final topic ill let u know lo

Answer 61

lol okay!