What type of conic section is given by the equation 4x^2+ 9y^2 = 36? What are its domain and range?
well the 4 and 9 tell us its not what?
No idea.
what is this graph x^2 + y^2 = 1?
not a circle :P
A circle?
its not a circle, its close. what is close to a circle?
zzr0ck, isnt x^2+y^2=1 a cirlce with center 0,0 and radius 1?
yes
Oh. So its an ellipse.
so what would happen if we did 4x^2 + 9x^2 = 1
yes @xkylex
It would be a circle
\[4x^2+ 9y^2 = 36\]\[{4x^2\over36}+{9y^2\over36}={36\over36}\]\[{x^2\over9}+{y^2\over4}=1\] \[{x^2\over a^2}+{y^2\over b^2}=1~~is~~an~~ellipse\] :)
zzr0ck that would be an ellipse, but what does the 4 and 9 mean exactly?
that is what is stretching it
@_@, im so confused.
a circle is 1*x^2 + 1*y^2 = 1
so it stretches it how much?
when we change the ones it changes
that's a hard question, for calculus
So how would I find the domain and range?
zzrock if you look at the graph of an ellipse, how can you make the equation from just looking at it??
you can get points and solve the equation yummy posted, they always have the same form
well technically you have to put it into the form of an equation of an ellipse before you graph it...the graph would look like this:|dw:1369973189718:dw|
OH!
The domain would be -3, 3. The range would be -2 2.
Is that right?
the domain would be \([-3,3]\) and the range would be \([-2,2]\)
Thank you everyone! If only I could give more than one medal :c .
\[a=3\]\[b=2\]\[c=\sqrt{5}\]\[focus:(-\sqrt{5},0)~~and~~(\sqrt{5},0}\]
strange question, this is not a function and thus to talk about its domain and range is pointless...
true, domain and range is pointless, I agree
Join our real-time social learning platform and learn together with your friends!