Question

Let u = <4,-1> and v = <3,5>. What is lu + vl rounded to the nearest hundredth?

Answer 1

That is suppose to be absolute values btw

Answer 2

do you know the distance function?

Answer 3

distance formula?

Answer 4

this is the norm of two vectors
norm(a,b) = || a - b || = || b - a || = sqrt((a_1)-(b_1))^2 + (a_2 - b_2)^2 + .......)

Answer 5

so you have sqrt((5-(-1))^2 + (3-4)^2) = sqrt(36+ 1) = sqrt(37)

Answer 6

Okay, is there more so do I just round that ?

Answer 7

*or not so

Answer 8

37 is prime I think

Answer 9

so yes round that

Answer 10

Okay, so would it be 6.1 ?

Answer 11

its Pythagoreans theorem

Answer 12

sure sounds about right

Answer 13

the answer should be larger than 6.1

Answer 14

how ?

Answer 15

u = <4,-1> and v = <3,5>

u+v = <4,-1>+<3,5>

u+v = <4+3,-1+5>

u+v = <7,4>

Answer 16

o wow I read minus, ...... sorry

Answer 17

|u+v| = sqrt(7^2+4^2)

|u+v| = sqrt(49+16)

|u+v| = sqrt(65)

|u+v| = 8.06225774829854

|u+v| = 8.06

Answer 18

Oh okay, that sounds a bit better. Thank you @jim_thompson5910

Answer 19

change my 5- to 5+ and 3- to 3+ and your good:) sorry

Answer 20

yw

Answer 21

Thats okay @zzr0ck3r I get what you did though (: