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Mathematics 16 Online
OpenStudy (anonymous):

If you were an Algebra 1 instructor and were creating a test on factoring trinomials of the form ax2 + bx + c, what do you think would be the easiest way to create a trinomial that can be factored? Provide one unique example

OpenStudy (anonymous):

take k(x-m)(x-n) generate random integral values for k, m and n convert to the form ax^2+bx+c

OpenStudy (anonymous):

so basically take two binomials and distribute?

OpenStudy (anonymous):

two binomials and a constant to make a≠1

OpenStudy (nurali):

The way that I would create factorable trinomials of the form ax^2 + bx + c is by making up two linear expressions and multiplying them together. This would give you a trinomial who's factors are the two linear expressions that were multiplied together. For example, I will pick 2x + 5 and 6x - 1 as my two linear expressions Multiplying them together (2x + 5)(6x - 1) gives 12x^2 - 2x + 30x - 5 = 12x^2 + 28x - 5, which is a factorable polynomial of the form ax^2 + bx + c

OpenStudy (anonymous):

muchas gracias !

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