Question

\[\Huge \color{red}{LOG_ IN}\]

Answer 1

Hmm -- that's actually very hard to read.

Answer 2

\[\large \log_12\log_21\log_31\log1_3...\log_{n-1}n=x\log _12\log_23\log_34...log _n(n-1)\]

Answer 3

is it ok now

Answer 4

\[ \log_12\log_21\log_31\log1_3...\log_{n-1}n=x\log _12\log_23\log_34...log _n(n-1)\]

Answer 5

:) color is soo much better

Answer 6

What does it even matter, this part
\[ \log_12\log_21\color{red}{\log_31}\log1_3...\log_{n-1}n=x\log _12\log_23\log_34...log _n(n-1)\]
is already zero -.-

Answer 7

yes thats correct ...mistake

Answer 8

wait its actually last one
\[\log_12\log_21\log_31\log_13...\log_1n=x\log _12\log_23\log_34...\log _n(n-1)\]

Answer 9

You still have a \(\large \log_31\) there...

Answer 10

Wait a minute... what is this even supposed to mean?
\[\log_12\log_21\log_31\color{red}{\log_13}...\log_1n=x\log _12\log_23\log_34...\log _n(n-1)\]

You know that that doesn't exist... -.-

Answer 11

sry this is what i want
let me explain how i wanted to phrase this ?

Answer 12

Hit me

Answer 13

\[\log_12\log _21\log_13\log_31 ...\log_1(n)\log_n1\]
such that if i use the property
\[\log _ab=\frac{ 1 }{ \log _ba }\]
hence
\[\log_12\frac{ 1 }{ \log _12 }\log _13\frac{ 1 }{ \log _31 }...\log_1n \frac{ 1 }{ \log_1 n}=1\]

Answer 14

Why is there even a log base 1 ?

Answer 15

so i see\[\log_12=x \implies 1^x=2\implies \emptyset\]

Answer 16

yup

Answer 17

how can i phrase such a question to work is it
\[\log_23\log_32\log_45\log_54...\log_n(n+1)\log_{n+1}n\]

Answer 18

These pairs (in respective colour) are all just equal to 1...
\[\color{red}{\log_23\log_32}\color{green}{\log_45\log_54}...\color{blue}{\log_n(n+1)\log_{n+1}n}\]

Answer 19

yes exaclty

Answer 20

Well, that seems to be it for this particular mess of logs :P

Answer 21

DO YOU KNOW HOW TO DEAL WITH RIGHT HAND SIDE

Answer 22

right hand side also has a log base 1

Answer 23

IF YOU APPLY CHANGE OF BASE YOU HAVE
\[\log _ab=\frac{ \log b }{ \log a }\]
with the same reasoning we only have\[nx=1\]

Answer 24

of course i will have to start again at an interger more than one

Answer 25

right

Answer 26

uhh...

Answer 27

The RHS is daunting... might need to get a second opinion on that :)