Question

Find the sum of the geometric series.

Answer 1

The sum of a geometric series:

x^0 + x^1 + x^2 + . . . + x^(n-2) + x^(n-1) + x^n is

[x^(n+1) - 1] / (x - 1)

Here, you have:

81[1 + (1/3)^1 + (1/3)^2 + . . . + (1/3)^6]

(81)[(1/3)^7 - 1] / [(1/3) - 1]

Answer 2

All good now, @ladyrosebud ?

Answer 3

Well I did that and keep getting the wrong answer. I get 121.4. Idk what it is

Answer 4

what are the directions on how the answer should be formatted?

Answer 5

I also get:

121.44444444444444444444444444444

Perhaps you are needing to put the answer in a different format?

Maybe fractions?

Answer 6

The answers are just regular numbers and fractions. Here's what they have
a. 1093/9
b.91
c.101
d.15/7

Answer 7

Oh it's A isn't it?

Answer 8

yes

Answer 9

first one

Answer 10

oh okay thanks!

Answer 11

uw!

Answer 12

Good luck to you in all of your studies and thx for the recognition! @ladyrosebud

Answer 13

Thank you:) and it really helped! I was just overlooking the answer, lol

Answer 14

You did well! np!