x^2+3=-4x how do u dolve this with the quadratic formula? Ive tryed 4 hours and keep geting the wrong answer...
put all terms on one side (the left one for example), and use the formula involving the discriminant \(\Delta\): the solutions are given by the formula \(-\frac{-b\pm\sqrt\Delta}{2a}\) (if the equation is \(ax^2+bx+c=0\))
Whats the discriminant?
it's the quantity noted \(\Delta\) , the value is \(b^2-4ac\).
the correct fraction is \(\frac{-b\pm\sqrt{\Delta}}{2a}\) (i put a minus sign in the first message that shouldn't be there)
Im gettting a triangle under that √, id that right?
yes. what is your \(\Delta\) ? if it's correct then you will most likely find the two solutions.
i don't know really what you did.. write \(x^2+3=-4x\) as \(x^2+4x+3=0\) and recognize the values of \(a,b,c\). Here \(a=1,b=4,c=3\).
ok. I didnt pout abc in that order, one sec
*put
4^2-4(1)(3) right so far?
yes.
3 and 1?
-1 and -3. i think. please check.
ur right
yup, then you got the answer.
|dw:1370035861176:dw|
Join our real-time social learning platform and learn together with your friends!