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Geometry 19 Online
OpenStudy (anonymous):

can you help me :) this is the problem

OpenStudy (anonymous):

|dw:1370021021557:dw|smaller side of angle bisected

OpenStudy (anonymous):

this is the question : what is the value of X ????? :)

OpenStudy (anonymous):

help please

OpenStudy (anonymous):

BD=16 ???

OpenStudy (anonymous):

x=20??

OpenStudy (jhannybean):

You know a full triangle is = 180 degrees. if BD is an angle bisector, it cuts the triangle's measurement in half.what is 180/2?

OpenStudy (jhannybean):

so we have the angle measurement of BDC = 90 degrees, now we can aply the pythagorean theorem on special RIGHT triangles.

OpenStudy (anonymous):

i know i'm try but i cant find the answer :((

OpenStudy (jhannybean):

c=12*

OpenStudy (anonymous):

YOU CANT ASSUME IT FORMS A PERPENDICULAR ANGLE

OpenStudy (anonymous):

its an angle bisector not a perpendicular bisector and if it were a perpendicular bisector, it would require the 2 sides to be the same

OpenStudy (jhannybean):

OK ok. fine. redrawing.

OpenStudy (anonymous):

after giving it some though, i believe you need to use the law of cosines to solve

OpenStudy (anonymous):

you know angle ABD and angle DBC are equal to each other

OpenStudy (anonymous):

BD IS 17.32 NOT 16

OpenStudy (anonymous):

is that given?

OpenStudy (anonymous):

NO, is according to my results of the pythagorean theorem

OpenStudy (jhannybean):

|dw:1370023304475:dw| Ok i guess we have to use pythagorean identity twice. use it on the first triange to find y, then use y and 12 to figure out x.

OpenStudy (anonymous):

.....

OpenStudy (anonymous):

please draw it to scale

OpenStudy (anonymous):

|dw:1370023470738:dw|

OpenStudy (anonymous):

ok amigo ya hice todo eso ..... i did all that and doen not gime me good results... :P

OpenStudy (anonymous):

thats cause its wrong.... you cannot apply the pythagorean theorem... then angles are not 90 degrees

OpenStudy (jhannybean):

Then how do you do this >:(

OpenStudy (anonymous):

ok , sorry ..

OpenStudy (anonymous):

is the proportion given?

OpenStudy (anonymous):

no ...

OpenStudy (jhannybean):

think you need atleast one angle... so you can use the angle bisector :\

OpenStudy (anonymous):

no... angle bisector is a concept.... a line that divides the angle into 2 seperate angles....

OpenStudy (anonymous):

if the angle is x then the 2 angles from the angle bisector would be x/2 ........

OpenStudy (anonymous):

no idea i never bother to actually do the problem trying it now

OpenStudy (anonymous):

thanks for your help guys, but i give up :(

OpenStudy (anonymous):

ahy lora you are so burra

OpenStudy (jhannybean):

|dw:1370024362758:dw|

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