can you help me :) this is the problem
|dw:1370021021557:dw|smaller side of angle bisected
this is the question : what is the value of X ????? :)
help please
BD=16 ???
x=20??
You know a full triangle is = 180 degrees. if BD is an angle bisector, it cuts the triangle's measurement in half.what is 180/2?
so we have the angle measurement of BDC = 90 degrees, now we can aply the pythagorean theorem on special RIGHT triangles.
i know i'm try but i cant find the answer :((
c=12*
YOU CANT ASSUME IT FORMS A PERPENDICULAR ANGLE
its an angle bisector not a perpendicular bisector and if it were a perpendicular bisector, it would require the 2 sides to be the same
OK ok. fine. redrawing.
after giving it some though, i believe you need to use the law of cosines to solve
you know angle ABD and angle DBC are equal to each other
BD IS 17.32 NOT 16
is that given?
NO, is according to my results of the pythagorean theorem
|dw:1370023304475:dw| Ok i guess we have to use pythagorean identity twice. use it on the first triange to find y, then use y and 12 to figure out x.
.....
please draw it to scale
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ok amigo ya hice todo eso ..... i did all that and doen not gime me good results... :P
thats cause its wrong.... you cannot apply the pythagorean theorem... then angles are not 90 degrees
Then how do you do this >:(
ok , sorry ..
is the proportion given?
no ...
think you need atleast one angle... so you can use the angle bisector :\
no... angle bisector is a concept.... a line that divides the angle into 2 seperate angles....
if the angle is x then the 2 angles from the angle bisector would be x/2 ........
no idea i never bother to actually do the problem trying it now
thanks for your help guys, but i give up :(
ahy lora you are so burra
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