Question

Find the area of the region bounded above by y = 4 and below by y = x^2.

Answer 1

If I'm not mistaken you can set it up as \[\int\limits_{-2}^{2}(4)-(x^2)dx\]

Answer 2

okay

Answer 3

@dan815

Answer 4

i get 16 - x^2

Answer 5

for a final answer..?

Answer 6

no after i integrated

Answer 7

\[4x-\frac{ x^3 }{ 3 }\]

Answer 8

ohh ok

Answer 9

so what do i do next?

Answer 10

plug in and subtract. So plug in the upper limit, then the lower limit and subtract the two

Answer 11

subtract the upper limit from the lower?

Answer 12

\[(8-\frac{ 8 }{ 3 })-(-8+\frac{ 8 }{ 3 })\]

Answer 13

that's what you get when you plug in 2 and -2.

Answer 14

okay