Question

please help :)

simplify. x/(4x) + x^2

Answer 1

I feel like I've done this problem so many times D:

Answer 2

@Luigi0210 (x do you know the answer?

Answer 3

\[\frac{ x(1) }{ x(4+x) }=\frac{ 1 }{ 4+x }\]

Answer 4

I'm not giving the answer directly :P

Answer 5

@Luigi0210 bleh.. confused

Answer 6

@phi @ash2326 help?

Answer 7

well you have to factor out an x, and then since they have the same factors you can cancel them out

Answer 8

D:
:(

Answer 9

@Luigi0210 1/4??

Answer 10

@Jhannybean help me out here

Answer 11

@.Sam. @Luigi0210 help me out?

Answer 12

\[\frac{x}{4x+x^2}\]
Factor x from denominator
\[=\frac{x}{x(4+x)}\]
cancel x
\[=\frac{\cancel x}{\cancel x(4+x)} \\ \\ =\frac{1}{4+x}\]

Answer 13

I tried explaining it :/

Answer 14

@.Sam. i love you. can you help me out with this? simplify. (-14x^3)(/x^3-5x^4)

Answer 15

@Luigi0210 aw, you helped too. :)

Answer 16

:(

Answer 17

Same thing, factor x^3 from denominator then cancel it

Answer 18

@.Sam. -14x/1x-5?

Answer 19

that looks like one of the choices, i.e. a pure guess.

Answer 20

should be
-14/1-5x

Answer 21

@.Sam. ohh

Answer 22

\[\frac{-14x^3}{x^3-5x^4}=\frac{-14\cancel{x^3}}{\cancel{x^3}(1-5x)}=\frac{-14}{1-5x}\]

Answer 23

@.Sam. ohhh, I see!

Answer 24

@.Sam. so for x+7/x^2+4x-2, would it be 1/x-7??

Answer 25

look at the denominator, looks like it can't be factored

Answer 26

@.Sam. you're right.. ach, i feel so stupid! :/

Answer 27

@.Sam. wait, is it 1/x-3?

Answer 28

no, if you cant factor, the answer will just be x+7/x^2+4x-2

Answer 29

@.Sam. but, that's not an option

Answer 30

maybe you wrote the question wrongly

Answer 31

@.Sam. no, that's the question

Answer 32

\[\Huge \frac{x+7}{x^2+4x-2}\]