Question

I need help with this please. O.o

Answer 1

force down due to barrel = \(m \times g\) = 1200 N
force down due to man = \(m \times g\) = 800 N

Next, find the net force of both man + barrel = 400 kg
Next, find mass of man + barrel = 120 + 80 = kg
Acceleration (a) = force / mass = 400 / 200 = 2 (m/s)/s
Now, find acceleration: \(a = \frac{F}{m} = ?\)
[HINT: Units are in \(\large \frac{\frac{m}{s}}{s}\)
Distance (s) man travels to meet barrel = 9 meters

Velocity from : \(v = \sqrt{ 2 \times a \times s }\)
v = 6 m/s

Answer 2

Thank you! :)