Question

Math help, please???????

Answer 1

@.Sam. Can you help me understand this? I'm able to redo a test, and I know the answer I just don't know how they did it.

Answer 2

\[\frac{1}{3 x+9}-\frac{2}{x+3}=2\]

Answer 3

Wait...what?

Answer 4

Ok, wait that's the problem oops.

Answer 5

First, common denominator to bring the fraction together.
Common denominator is 3(x+3)

Answer 6

Do you get
\[-\frac{5}{3 (x+3)}=2\]

Answer 7

Okay, let me write that down.

Answer 8

Wait, so for the number 5 do I add the two twos and 1 to get 5?

Answer 9

@.Sam.

Answer 10

\[\frac{1}{3 x+9}-\frac{2}{x+3}=2 \\ \\ \frac{1}{3( x+3)}-\frac{2}{x+3}=2 \\ \\ \frac{1}{3( x+3)}-\frac{2}{(x+3)}\color{blue}{\frac{\times 3}{\times 3}}=2 \\ \\ \frac{1-6}{3( x+3)}=2 \\ \\ \frac{-5}{3(x+3)}=2\]

Answer 11

Then multiply both sides by 3(x+3)
\[-5=2(3)(x+3) \\ \\ -5=6(x+3) \\ \\ \frac{-5}{6}=x+3 \\ \\ -\frac{5}{6}-3=x \\ \\ x=-\frac{23}{6}\]

Answer 12

@.Sam. How did you get the 23?

Answer 13

Wait, never mind. I know.