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OpenStudy (anonymous):

PLZ HELP!!! See attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Luis_Rivera so i'll take that as you don't know how to do it?

OpenStudy (anonymous):

@amistre64 can you help with this?

OpenStudy (amistre64):

which part is giving you room to pause?

OpenStudy (anonymous):

all of it

OpenStudy (amistre64):

lets work on the test stat first, what do you recall about computing a tscore?

OpenStudy (amistre64):

\[t=\frac{\bar x-\mu}{s}\sqrt n\]

OpenStudy (anonymous):

oh ok i thought that was the formula but i wasn't sure.

OpenStudy (amistre64):

#3 suggests that you recall something about hypt testing to begin with if we are looking for < or > its in a tail; if we are looking for =, its in both tails

OpenStudy (anonymous):

When you say #3 you mean question c)?

OpenStudy (amistre64):

part d, or #4 (i thought they was numbered) would suggest that the red is inbetween 2 values ...

OpenStudy (anonymous):

for b) i did \[\frac{ 102.0-105 }{ \frac{ 5.8 }{ \sqrt{35} } }\] =-0.09

OpenStudy (amistre64):

your setup is correct, but your calculation is off

OpenStudy (anonymous):

i put it into mathway and it came out as 0.0874. so that makes it 0.09 right?

OpenStudy (amistre64):

102-105 = -3 -3/5.8 = -0.51724 -0.51724 * sqrt(35) = -3.060...

OpenStudy (anonymous):

so the answer would be -3.06?

OpenStudy (amistre64):

thats what my ti83 gives me, yes

OpenStudy (amistre64):

the standard deviation is 5.8/sqrt(35); or about .98 we are 3 to the left of center, giving us a little over -3 sds away

OpenStudy (anonymous):

i'm getting something different. 102.0-105=-3 -3/5.8=-0.5172413793 -0.5172413793/sqrt(35)=-0.08742975049=-0.09

OpenStudy (amistre64):

your not spose to divide that by sqrt(35)

OpenStudy (amistre64):

\[\frac{a}{p/q}=\frac{a}{p}*q\]

OpenStudy (amistre64):

if anything, 5.8/sqrt(35) = .98 -3/.98 = -3.06

OpenStudy (anonymous):

ok i see that now.

OpenStudy (amistre64):

part c has me a little confused, my book is stating a path: type of test? two tailed (since H0 not= H1 hyp) tstat to the left of right? ours is left since its negative therefore Pvalue = 2x the area to the left of the t score

OpenStudy (amistre64):

its twice the area since its 2 tailed ... got it

OpenStudy (anonymous):

so c) is B?

OpenStudy (amistre64):

thats what i had originally considered, and thats what im going with :)

OpenStudy (anonymous):

ok Is a) B?

OpenStudy (amistre64):

my gut says no. but quite frankly i never was good at that kind of question. I want to say it yes, but cant really say why

OpenStudy (anonymous):

well whats you're gut say it is?

OpenStudy (amistre64):

my gut likes d, but its lied to me before :) on c, my book shows the pvalue area redshaded to the left, and says the pvalue is twice the area shaded ... which has me thinking that c is also just left shaded

OpenStudy (anonymous):

then i will go with that. :)

OpenStudy (anonymous):

now d)

OpenStudy (amistre64):

how do you normally find the area? ti83 by chance?

OpenStudy (anonymous):

no by hand or google

OpenStudy (amistre64):

well, our zscore is -3.06 :) and we want the area to the left of it

OpenStudy (anonymous):

so that would be...?

OpenStudy (amistre64):

i thought you had indicated that you could find that area .... by hand or by google

OpenStudy (amistre64):

http://www.danielsoper.com/statcalc3/calc.aspx?id=2

OpenStudy (anonymous):

that's confusing. 1.25 means...?

OpenStudy (amistre64):

1.25 is just a primer, our z score we found is -3.06 enter it into the box and hit calculate, it will give you the cumulative area up to z = -3.06

OpenStudy (anonymous):

it gave me 0.00110668

OpenStudy (amistre64):

im thinking that this is the lower bound, the area that is in the "red" we want to double that for an upper bound.

OpenStudy (anonymous):

i'm thinking d) is A

OpenStudy (amistre64):

...me too, but then again im only going off of what im reading in my stats book. if in reading it incorrectly, then i cant really guarentee the accuracy of my "guidance"

OpenStudy (amistre64):

my ti83 gives a T-test, p-value of .004, which is not a range like the options .... nor is it really in the range of .001 to .002 ....

OpenStudy (amistre64):

of course that next question has alot of 4s in it .004 * 1000 = 4

OpenStudy (anonymous):

ok that means...?

OpenStudy (amistre64):

at the moment, that means im conflicted between what the book says, and what the overall problem set is telling us. if p = .004, that would suggest that our range is between 002 and 005, but thats not the results i get from doing the process in the book. I simply dont have enough experience at this to know what, if anything, i am doing wrong :/

OpenStudy (anonymous):

well whats your best guess?

OpenStudy (anonymous):

i'd go with the book.

OpenStudy (amistre64):

lol, the book doesnt jive with the next problem tho, so im thinking ive missed something. ti83 and the test stat by hand each give us -3.06 this should be the zscore value as well, unless there is some z to t adjustment that im missing

OpenStudy (anonymous):

lol well i'll take a guess cause this problem is giving me a headache. lol

OpenStudy (amistre64):

give me about 10 minutes to review a youtube :)

OpenStudy (anonymous):

lol ok

OpenStudy (amistre64):

got it

OpenStudy (amistre64):

we should not have used the "normal" distribution with a t-score

OpenStudy (amistre64):

when i use the tCDF, with 1 degree of freedom: tCDF(-9999,-3.06,35-1) = .00215 and doubled is .00430

OpenStudy (anonymous):

?

OpenStudy (amistre64):

in short, i assumed the t = z .... so our Pvalue is between .0021 and .0043

OpenStudy (amistre64):

this will correspond to the next problem

OpenStudy (anonymous):

so c) is C?

OpenStudy (amistre64):

im going with C, yes :)

OpenStudy (anonymous):

so to Interpret that it would be...?

OpenStudy (amistre64):

well, to guide you to this, we just tested a mean of 102, and it has a Pvalue (probability value) of .4 % .... or .4 in every 100 how would you use this to determine (d) ?

OpenStudy (amistre64):

if you expected to be paid: .004 cents for every hour you worked how much would you make in 10 hours? in 100? in 1000?

OpenStudy (anonymous):

.004*10?

OpenStudy (amistre64):

yes, so .04 cents for 10 hours ... and for 100?

OpenStudy (anonymous):

0.4

OpenStudy (amistre64):

good, 100 for .4 match an option? or do we need to go to 1000?

OpenStudy (anonymous):

well 1000 is 4

OpenStudy (amistre64):

so, its either B or C notice that the name on our little paycheck is "102" since thats what this Pvalue is attributed to

OpenStudy (amistre64):

we should expect that in 1000 hours, mister 102 will be paid 4

OpenStudy (anonymous):

so it's C?

OpenStudy (amistre64):

gut says C :)

OpenStudy (anonymous):

good now e)

OpenStudy (amistre64):

(e) has to do with something im more familar with, a confidence interval

OpenStudy (amistre64):

the area to reject the is termed alpha, that a looking thing

OpenStudy (amistre64):

the expected value of a = .01 our pvalue is at best: .004 we rejecct the null hypotheses if the pvalue is less then or equal to the "a" value

OpenStudy (anonymous):

so it's yes?

OpenStudy (amistre64):

correct

OpenStudy (anonymous):

Great! got time to help with 1 more short question?

OpenStudy (amistre64):

not really, i have to be heading home.

OpenStudy (anonymous):

lol ok thx for the help!

OpenStudy (amistre64):

good luck with this :)

OpenStudy (anonymous):

THX!

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