PLZ HELP!!! See attachment.
@Luis_Rivera so i'll take that as you don't know how to do it?
@amistre64 can you help with this?
which part is giving you room to pause?
all of it
lets work on the test stat first, what do you recall about computing a tscore?
\[t=\frac{\bar x-\mu}{s}\sqrt n\]
oh ok i thought that was the formula but i wasn't sure.
#3 suggests that you recall something about hypt testing to begin with if we are looking for < or > its in a tail; if we are looking for =, its in both tails
When you say #3 you mean question c)?
part d, or #4 (i thought they was numbered) would suggest that the red is inbetween 2 values ...
for b) i did \[\frac{ 102.0-105 }{ \frac{ 5.8 }{ \sqrt{35} } }\] =-0.09
your setup is correct, but your calculation is off
i put it into mathway and it came out as 0.0874. so that makes it 0.09 right?
102-105 = -3 -3/5.8 = -0.51724 -0.51724 * sqrt(35) = -3.060...
so the answer would be -3.06?
thats what my ti83 gives me, yes
the standard deviation is 5.8/sqrt(35); or about .98 we are 3 to the left of center, giving us a little over -3 sds away
i'm getting something different. 102.0-105=-3 -3/5.8=-0.5172413793 -0.5172413793/sqrt(35)=-0.08742975049=-0.09
your not spose to divide that by sqrt(35)
\[\frac{a}{p/q}=\frac{a}{p}*q\]
if anything, 5.8/sqrt(35) = .98 -3/.98 = -3.06
ok i see that now.
part c has me a little confused, my book is stating a path: type of test? two tailed (since H0 not= H1 hyp) tstat to the left of right? ours is left since its negative therefore Pvalue = 2x the area to the left of the t score
its twice the area since its 2 tailed ... got it
so c) is B?
thats what i had originally considered, and thats what im going with :)
ok Is a) B?
my gut says no. but quite frankly i never was good at that kind of question. I want to say it yes, but cant really say why
well whats you're gut say it is?
my gut likes d, but its lied to me before :) on c, my book shows the pvalue area redshaded to the left, and says the pvalue is twice the area shaded ... which has me thinking that c is also just left shaded
then i will go with that. :)
now d)
how do you normally find the area? ti83 by chance?
no by hand or google
well, our zscore is -3.06 :) and we want the area to the left of it
so that would be...?
i thought you had indicated that you could find that area .... by hand or by google
that's confusing. 1.25 means...?
1.25 is just a primer, our z score we found is -3.06 enter it into the box and hit calculate, it will give you the cumulative area up to z = -3.06
it gave me 0.00110668
im thinking that this is the lower bound, the area that is in the "red" we want to double that for an upper bound.
i'm thinking d) is A
...me too, but then again im only going off of what im reading in my stats book. if in reading it incorrectly, then i cant really guarentee the accuracy of my "guidance"
my ti83 gives a T-test, p-value of .004, which is not a range like the options .... nor is it really in the range of .001 to .002 ....
of course that next question has alot of 4s in it .004 * 1000 = 4
ok that means...?
at the moment, that means im conflicted between what the book says, and what the overall problem set is telling us. if p = .004, that would suggest that our range is between 002 and 005, but thats not the results i get from doing the process in the book. I simply dont have enough experience at this to know what, if anything, i am doing wrong :/
well whats your best guess?
i'd go with the book.
lol, the book doesnt jive with the next problem tho, so im thinking ive missed something. ti83 and the test stat by hand each give us -3.06 this should be the zscore value as well, unless there is some z to t adjustment that im missing
lol well i'll take a guess cause this problem is giving me a headache. lol
give me about 10 minutes to review a youtube :)
lol ok
got it
we should not have used the "normal" distribution with a t-score
when i use the tCDF, with 1 degree of freedom: tCDF(-9999,-3.06,35-1) = .00215 and doubled is .00430
?
in short, i assumed the t = z .... so our Pvalue is between .0021 and .0043
this will correspond to the next problem
so c) is C?
im going with C, yes :)
so to Interpret that it would be...?
well, to guide you to this, we just tested a mean of 102, and it has a Pvalue (probability value) of .4 % .... or .4 in every 100 how would you use this to determine (d) ?
if you expected to be paid: .004 cents for every hour you worked how much would you make in 10 hours? in 100? in 1000?
.004*10?
yes, so .04 cents for 10 hours ... and for 100?
0.4
good, 100 for .4 match an option? or do we need to go to 1000?
well 1000 is 4
so, its either B or C notice that the name on our little paycheck is "102" since thats what this Pvalue is attributed to
we should expect that in 1000 hours, mister 102 will be paid 4
so it's C?
gut says C :)
good now e)
(e) has to do with something im more familar with, a confidence interval
the area to reject the is termed alpha, that a looking thing
the expected value of a = .01 our pvalue is at best: .004 we rejecct the null hypotheses if the pvalue is less then or equal to the "a" value
so it's yes?
correct
Great! got time to help with 1 more short question?
not really, i have to be heading home.
lol ok thx for the help!
good luck with this :)
THX!
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